A triangular clock has sides measuring 16 cm, 12 cm, and 20 cm. What is the area to the nearest square centimeter?

What is y = 5 and it’s slope

e-lub [12.9K]

Answer:

what do you mean bro ?

Step-by-step explanation:

8 0

3 years ago

Given the equation 4x − 26 = 2x − 4, which order of operations completely solves for x?

scoray [572]

4x - 26 = 2x - 4....subtract 2x from both sides
4x - 2x - 26 = -4...add 26 to both sides
4x - 2x = -4 + 26...combine terms
2x = 22...divide both sides by 2
x = 22/2 = 11

OR
4x - 26 = 2x - 4.....subtract 4x from both sides
-26 = 2x - 4x - 4....add 4 to both sides
-26 + 4 = 2x - 4x...combine terms
-22 = -2x....divide both sides by -2
-22/-2 = x
11 = x

6 0

3 years ago

Find the area of the shaded region

Dimas [21]

The area of the shaded region is 15.453 square units.

Step-by-step explanation:

Step 1:

The given shape consists of a rectangle and two circles.

The length of the rectangle is given as 12 cm. Both the diameters of the circles equal 12 cm. So each circle has a diameter of 6 cm and thus a radius of 3 cm.

The diameter of the circle is equal to the width of the rectangle.

So the rectangle has a length of 12 cm and a width of 6 cm. The circles have radii of 3 cm each.

Step 2:

The area of the rectangle $= (l)(w) = (12)(6) = 72$ square cm.

The area of each circle $= \pi r^{2} = (3.1415)(3^{2} ) = 28.2735$ square cm.

The area of both circles $=2(28.2735) = 56.547$ square cm.

The area of the shaded region is the difference between the area of the rectangle and the area of both circles.

The area of the shaded region $= 72 - 56.547 = 15.453$ square units.

The area of the shaded region is 15.453 square units.

6 0

3 years ago

The square of the difference of two numbers

emmasim [6.3K]

Answer: The difference between consecutive square numbers is always odd. The difference is the sum of the two numbers that are squared. ... The difference between alternate square numbers is always even; it is twice the sum of the two numbers that are squared.

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

A television station plans to ask a random sample of 400 city residents if they can name the news anchor on the evening news at

hodyreva [135]

Answer:

There is an 8.38% probability that the anchor will be fired.

Step-by-step explanation:

For each resident, there is only two possible outcomes. Either they can name the news anchor on the evening news at their station, or they cannot.

This means that the binomial probability distribution will be used in our solution.

However, we are working with samples that are considerably big. So i am going to aaproximate this binomial distribution to the normal.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

$E(X) = np$

The standard deviation of the binomial distribution is:

$\sqrt{V(X)} = \sqrt{np(1-p)}$

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that $\mu = E(X), \sigma = \sqrt{V(X)}$ .

In this problem, we have that:

400 city residents are going to be asked. So $n = 400$ .

Suppose that in fact 12% of city residents could name the anchor if asked. This means that $p = 0.12$ .

So,

$\mu = E(X) = 400*0.12 = 48$

$\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{400*0.12*0.88} = 6.5$ .

They plan to fire the news anchor if fewer than 10% of the residents in the sample can do so.

What is the approximate probability that the anchor will be fired?

10% of the residents is 0.10*400 = 40 residents.

Fewer than 10% is 39 residents. So the probability that the anchor will be fired is the pvalue of Z when $X = 39$ .

So:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{39 - 48}{6.5}$

$Z = -1.38$

$Z = -1.38$ has a pvalue of 0.0838. This means that there is an 8.38% probability that the anchor will be fired.

5 0

3 years ago