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IgorLugansk [536]
3 years ago
11

Help on this please asap

Mathematics
1 answer:
Juli2301 [7.4K]3 years ago
3 0

Answer:

87.75

Step-by-step explanation:

You are correct

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What is the relationship between age and savings rates? What might be some explanations for this?
s2008m [1.1K]
Wish I could help, sorry
4 0
3 years ago
Which one of the triangles shown is the image of the other triangle after dilation?What are the coordinates of the center of dil
Tanya [424]

Answer:

a) ΔF'G'H' is the image of ΔFGH

b)Center of dilation  (7,-1)

c) Scale factor: \frac{1}{2}

Step-by-step explanation:

Question a

Since the smaller triangle is named F'G'H', it means that, it is the image of triangle FGH.

Question B.

To find the center of dilation, draw straight lines through any two corresponding points.

The straight lines will meet at (7,-1).

This is called the center of dilation.

See graph in attachment.

Question c

The scale factor of the dilation is given by;

k=\frac{|F'G'|}{|FG|}

k=\frac{\sqrt{(4-5)^2+(1-5)^2}}{\sqrt{(3-1)^2+(3-11)^2}}

k=\frac{\sqrt{1+16}}{\sqrt{4+64}}

k=\frac{\sqrt{17}}{\sqrt{68}}

k=\frac{\sqrt{17}}{2\sqrt{17}}

k=\frac{1}{2}

7 0
3 years ago
In a race, 47 out of the 50 swimmers finished in less than 35 minutes. What percentage of the swimmers finished the race less th
Dmitry [639]

Answer:

94%

47*2=94

50*2=100

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Can anyone simplify 24q2/8q-3
Morgarella [4.7K]
24q^2 / 8q^-3

lets break this down...
24/8 = 3

q^2 / q^-3....when dividing exponents with the same base, keep the base and subtract the exponents. q^2 / q^-3 = q^(2 -(-3) = q^(2 + 3) = q^5

put them together and u get : 3q^5
4 0
4 years ago
A positive binary number is even precisely when its last digit is 0. When is a negative 2's complement number even?
Alex

Answer:

A negative 2’s complement number is even precisely when its last digit is 0 as well.

Step-by-step explanation:

Proof part 1: Assume there exists a 2’s complement negative even number which ends with 1. We  can, therefore, express this number as

1 ..... 1  = - (2’s complement of 1 ....1)

         = - (0 ...  1 )

         ≠ even

Since we know precisely that a positive binary number is not even when it ends with a 1. This is  a conflict with our assumption. Our assumption is, therefore, wrong.

Proof part 2: Assume there exists a 2’s complement negative odd number which ends with 0. We  can, therefore, express this number as

1 ..... 0  = - (2’s complement of 1 ....0)

         = - (0 ...  0 )

         = even

Since we know precisely that a positive binary number is even when it ends with a 0. This is a  conflict with our assumption. Our assumption is, therefore, wrong.

4 0
4 years ago
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