Answer:14
(1p-2)
Step-by-step explanation:
The GCF for 14 is 14
The GCF for 28 is 14
You use this equation to get 14p-28
Tell me if I have anything incorrect
Okay!
1. (12,12)
2. (10,14)
3. (8,16)
4. (6,18)
5. (4,20)
6. (2,22)
Hope this helped!
:)
Answer:
Height = 20 ; Base = 5
Step-by-step explanation:
Triangle Area = Base x Height x 1/2
50 = 1x × 4x × 1/2
50 = 4x^2 × 1/2
50 = 2x^2
25 = x^2
x=5
Height equals to 4x -> 4 × 5 = 20
Base equals to x -> 1 × 5 = 5
Answer:
D
Step-by-step explanation:
The average rate of change of a function over an interval a ≤ x ≤ b is found by:

Here, a is 0 and b is 3, so: 
Just plug in 3 for the first term and 0 for the second term in the numerator:
- First term: 
- Second term: 
So, the final answer is:
![\frac{[\frac{1}{2} (3^{3\frac{1}{2} })+3]-[\frac{1}{2} (3^{\frac{1}{2} })+3]}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B%5B%5Cfrac%7B1%7D%7B2%7D%20%283%5E%7B3%5Cfrac%7B1%7D%7B2%7D%20%7D%29%2B3%5D-%5B%5Cfrac%7B1%7D%7B2%7D%20%283%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%29%2B3%5D%7D%7B3%7D)
Thus, the answer is D.
Hope this helps!
Answer:
Step-by-step explanation:
Given the functions
F(x) = 6-x²
G(x) = x²+4x-12
A) we are to find F(x)+g(x)
F(x)+G(x) = 6-x²+x²+4x-12
F(x)+G(x) = 6+0+4x-12
F(x)+G(x) = 4x+6-12
F(x)+G(x) = 4x-6
The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER
F(x)-g(x) = 6-x²-(x²+4x-12)
F(x)-g(x) = 6-x²-x²-4x+12
F(x)-g(x) = 6-2x²+4x+12
F(x)-g(x) = -2x²+4x+6
The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER
3) F(x)/G(x)
= 6-x²/x²+4x-12
The domain of the function is the values of x for which the expression exists. The expression exists on all real interval i.e xER