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Klio2033 [76]
3 years ago
8

Factorize the following: cosB + 5cosB - 6​

Mathematics
2 answers:
Nady [450]3 years ago
7 0

Answer:

6(cosB - 1)

<em>BRAINLIEST, PLEASE!</em>

Step-by-step explanation:

cosB + 5cosB - 6

6cosB - 6

6(cosB - 1)

Dima020 [189]3 years ago
5 0

\\ \rm\Rrightarrow cosB+5cosB-6

  • Add cos

\\ \rm\Rrightarrow (1+5)cosB-6

\\ \rm\Rrightarrow 6cosB-6

  • Take 6 common

\\ \rm\Rrightarrow 6(cosB-1)

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Step-by-step explanation:

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3 0
3 years ago
What is the product of (2x+3) and (4x^2-6x+9)?​
gogolik [260]

Answer:

=8x^3+27

Step-by-step explanation:

First you are going to multply 2x by all of the other numbers in the 2nd parentheses, then do the same with 3. By doing this you should get and answer then combine like terms.

4 0
3 years ago
Unit rate feet per second 180 miles over 2 hours
Tatiana [17]
So that is equal to 180 miles per 2 hours which is 90 miles per hour if each hour has the same m/hr rate.
You can set up a proportion:
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\frac{x}{180} = \frac{1}{2}
cross multiply and you get
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divide both sides by 2 and you get
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5 0
3 years ago
The value of a house decreases at a steady rate of 20% each year. What is the total percentage loss (to the nearest integer) in
Westkost [7]

Answer: The total percentage loss would be 67%.

Step-by-step explanation:

Since we have given that

Rate of decline each year = 20%

Number of years = 5

We need to find the total percentage loss in value of the house at the end of 5 years.

So, Total percentage loss would be

1-(1-\dfrac{r}{100})^5\\\\=1-(1-\dfrac{20}{100})^5\\\\=1-(\dfrac{4}{5})^5\\\\=1-(0.8)^5\\\\=0.67\\\\\approx 67%

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8 0
3 years ago
The population of a town is 6500 and is increasing at a rate of 4% each year. Create a function for this scenario. At this rate,
Stella [2.4K]

Answer:

P_4 = 7604.08

Step-by-step explanation:

If the population increases at a rate of 4% per annum, then:

In year 1:

P_1 = P_0 + 0.04P_0

Where P_0 is the initial population and P_n is the population in year n

In year 2

P_2 = P_1 + 0.04P_1

It can also be written as:

P_2 = P_0 + 0.04P_0 + 0.04 (P_0 + 0.04P_0)

Taking out common factor P_0

P_2 = (1 + 0.04) (P_0) + 0.04P_0 (1 + 0.04)

Taking out common factor (1 + 0.04)

P_2 = (1 + 0.04) (P_0 + 0.04P_0)

Taking out again common factor P_0

P_2 = (1 + 0.04) (1 + 0.04) P_0

Simplifying

P_2 = P_0 (1 + 0.04) ^ 2


So

P_n = P_0 (1 + 0.04) ^ n

This is the equation that represents the population for year n

Then, in 4 years, the population will be:

P_4 = P_0 (1 + 0.04) ^ 4\\P_4 = 6500(1 + 0.04) ^ 4\\P_4 = 7604.08

3 0
3 years ago
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