Answer:
10.20% probability that a randomly chosen book is more than 20.2 mm thick
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
250 sheets, each sheet has mean 0.08 mm and standard deviation 0.01 mm.
So for the book.

What is the probability that a randomly chosen book is more than 20.2 mm thick (not including the covers)
This is 1 subtracted by the pvalue of Z when X = 20.2. So



has a pvalue of 0.8980
1 - 0.8980 = 0.1020
10.20% probability that a randomly chosen book is more than 20.2 mm thick
D. is your answer
4/x^2
hope it helps
Answer:
y = 3, y = 5, y = -1
Step-by-step explanation:
What you do is you substitute the x values into the x.
<em>y + 2(-1) = 5</em>
<em>y + -2 = 5</em>
y = 3
<em>y + 2(0) = 5</em>
y = 5
<em>y + 2(4) = 5</em>
<em>y + 6 = 5</em>
y = -1.
The length is determined by multiplying the number of balls with the diameter. The answer that would come out of this is in units of centimeters.
L = (6.02 x 10^23 balls)(4 cm/ball)
L = 2.408 x 10^24 cm
Then, we use the proper conversion factor to convert centimeter to kilometer.
L = (2.408 x 10^24 cm)(1 m/100 cm)(1 km/1000 m)
L = (2.408 x 10^24)(10^5)
The answer to this item is 2.408 x 10^19 km.
Answer:
25
Step-by-step explanation:
30-60-90 Triangles
short leg = x
long leg = x
hypotenuse = 2x