Help me please if i get less than an 80 i will not be able to do anything and will get grounded

Translate the word phrase into a math expression.

mote1985 [20]

Answer:

its d cuz im a big brain :)

7 0

2 years ago

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Given that set A has 48 elements and set B has 21 elements, determine each of the following. (a) The maximum possible number of

yKpoI14uk [10]

Answer: The required answers are

(a) 69, (b) 21, (c) 21 and (d) 0.

Step-by-step explanation: We are given that the set A has 48 elements and the set B has 21 elements.

(a) To determine the maximum possible number of elements in A ∪ B.

If the sets A and B are disjoint, that is they do not have any common element. Then, A ∩ B = { } ⇒ n(A ∩ B) = 0.

From set theory, we have

$n(A\cup B)=n(A)+n(B)-n(A\cap B)=48+21-0=69.$

So, the maximum possible number of elements in A ∪ B is 69.

(b) To determine the minimum possible number of elements in A ∪ B.

If the set B is a subset of set A, that is all the elements of set B are present in set A. Then, n(A ∩ B) = 21.

From set theory, we have

$n(A\cup B)=n(A)+n(B)-n(A\cap B)=48+21-21=48.$

So, the minimum possible number of elements in A ∪ B is 21.

(c) To determine the maximum possible number of elements in A ∩ B.

If the set B is a subset of set A, that is all the elements of set B are present in set A. Then, n(A ∩ B) = 21.

So, the maximum possible number of elements in A ∩ B is 21.

(d) To determine the minimum possible number of elements in A ∩ B.

If the sets A and B are disjoint, that is there is no common element in the sets A and B . Then, n(A ∩ B) = 0.

So, the maximum possible number of elements in A ∩ B is 0.

Thus, the required answers are

(a) 69, (b) 21, (c) 21 and (d) 0.

6 0

3 years ago

Write a phrase for each algebraic expression s+7

IRINA_888 [86]

An algebraic expression could be s plus 7

3 0

3 years ago

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Nikolai is taking a taxi to school. He has to

adoni [48]

7 because the first mile will be 3 dollars then if you add the rest of the miles it will be seven because you are adding four more miles

5 0

2 years ago

According to a survey, high school girls average 100 text messages daily (The Boston Globe, April 21, 2010). Assume the populati

Ghella [55]

Answer:

Step-by-step explanation:

Hello!

The variable of interest is:

X: number of daily text messages a high school girl sends.

This variable has a population standard deviation of 20 text messages.

A sample of 50 high school girls is taken.

The is no information about the variable distribution, but since the sample is large enough, n ≥ 30, you can apply the Central Limit Theorem and approximate the distribution of the sample mean to normal:

X[bar]≈N(μ;δ²/n)

This way you can use an approximation of the standard normal to calculate the asked probabilities of the sample mean of daily text messages of high school girls:

Z=(X[bar]-μ)/(δ/√n)≈ N(0;1)

a.

P(X[bar]<95) = P(Z<(95-100)/(20/√50))= P(Z<-1.77)= 0.03836

b.

P(95≤X[bar]≤105)= P(X[bar]≤105)-P(X[bar]≤95)

P(Z≤(105-100)/(20/√50))-P(Z≤(95-100)/(20/√50))= P(Z≤1.77)-P(Z≤-1.77)= 0.96164-0.03836= 0.92328

I hope you have a SUPER day!

3 0

2 years ago