The first one is a maximum and the a.s. is x=1
The second one is a minimum and the a.s. is x=-2
Answer:
(2x+1)(1) = 84. 2x+1= 84. 2x = 83.
Step-by-step explanation:
Answer :Plotting the points into the coordinate plane gives us an observation that this quadrilateral with vertices d(0,0), i(5,5) n(8,4) g(7,1) is a KITE, as shown in figure a.
Step-by-step explanation:
Considering the quadrilateral with vertices
d(0,0)
i(5,5)
n(8,4)
g(7,1)
Plotting the points into the coordinate plane gives us an observation that this quadrilateral with vertices d(0,0), i(5,5) n(8,4) g(7,1) is a KITE, as shown in figure a.
From the figure a, it is clear that the quadrilateral has
Two pairs of sides
Each pair having two equal-length sides which are adjacent
The angles being equal where the two pairs meet
Diagonals as shown in dashed lines cross at right angles, and one of the diagonals does bisect the other - cuts equally in half
Please check the attached figure a.
Answer:
The sum of the first 650 terms of the given arithmetic sequence is 2,322,775
Step-by-step explanation:
The first term here is 4
while the nth term would be ai = a(i-1) + 11
Kindly note that i and 1 are subscript of a
Mathematically, the sum of n terms of an arithmetic sequence can be calculated using the formula
Sn = n/2[2a + (n-1)d)
Here, our n is 650, a is 4, d is the difference between two successive terms which is 11.
Plugging these values, we have
Sn = (650/2) (2(4) + (650-1)11)
Sn = 325(8 + 7,139)
Sn = 325(7,147)
Sn = 2,322,775
Answer:
The correct option is (b).
Step-by-step explanation:
If X 
N (µ, σ²), then 
, is a standard normal variate with mean, E (Z) = 0 and Var (Z) = 1. That is, Z N (0, 1).
The distribution of these z-variate is known as the standard normal distribution.
The mean and standard deviation of the active minutes of students is:
<em>μ</em> = 60 minutes
<em>σ </em> = 12 minutes
Compute the <em>z</em>-score for the student being active 48 minutes as follows:
Thus, the <em>z</em>-score for the student being active 48 minutes is -1.0.
The correct option is (b).
