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Novosadov [1.4K]

3 years ago

12

Find the missing side of this triangle

1 answer:

Taya2010 [7]3 years ago

4 0

Answer:

5* $\sqrt{3}$

Step-by-step explanation:

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Can someone help me PLEASE

Arisa [49]

<u>Let's solve this problem step-by-step</u>:

$7 * 9 = (7*10)-(7*x)$

<em>x: it is the delta in the equation given in your picture</em>

<em />

<u>We know (7*10) - (7*x) is equivalent to the 7*(10-x)</u>

⇒ based on the Distributive Properties

$a*(b+c) = ab + ac$

$7*(10+(-x))=(7*10)+(7*(-x)=(7*10)-(7*x)$

<em />

<em> </em><u>So:</u>

<em> </em> $7*9=7(10-x)\\9=10-x\\x=10-9\\x= 1$

<u>Thus delta (the little triangle in this problem) in this case is 1</u>

<u></u>

<u>Answer: 1</u>

<u></u>

Hope that helps!

7 0

3 years ago

WHOEVER ANSWERS FIRST GETS BRAINLIEST

omeli [17]

Answer:

Part E.

Wendell’s dog, Jordan, was getting in his way as he worked in the backyard. So, Wendell chained him to a pole. If the chain is 12 feet long, about how much area does Jordan have to walk around?

Step-by-step explanation:

6 0

3 years ago

How do u solve <br>3 (x+8) - 3x ?

mariarad [96]

PEMDAS

paranthesis exponents multiplication division addition subtraction

3 0

3 years ago

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Simplify (6m2-5m+4)+(7m2+2m-5)

laiz [17]

Answer:13m2 - 3m - 1 i think that is the answer

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

11. What is the location of the vertex of the parabola defined by f(x) = −3x2 − 18x − 35 and in what direction does the parabola

lbvjy [14]

11. The given parabola has equation: $f(x)=-3x^2-18x-35$

We complete the square to have the function in the vertex form: $f(x)=-3(x^2+6x)-35$

$f(x)=-3(x^2+6x+9)+3*9-35$

$f(x)=-3(x^2+6x+9)+27-35$

$f(x)=-3(x+3)^2-8$

The vertex is (-3,-8), the graph opens down because a=-3<0

Ans: B. Vertex: (−3, −8), opens downward

12. We know the graph of $y=x^2$ is a parabola that opens up and has its minimum point at the origin.

The range of this function is $y\ge 0$

A straight line that has its y-intercept below the x-axis (y=3x-6) will not intersect $y=x^2$ and hence will form a system with no solution.

Ans: D. y equals x squared, y equals 3x minus 6

14. We want to find the zeros of $x^2+21x=5x-63$

$x^2+21x-5x+63=0$

$x^2+16x+63=0$

The factored form is $(x+7)(x+9)=0$

$x=-7\:or\: x=-9$

Ans: C. x = −7, −9

15. The given quadratic expression is $6x^2-17x+10$

We split the middle term to obtain:

$6x^2-12x-5x+10=0$

We factor by grouping to get:

$6x(x-2)-5(x-2)=0$

$(x-2)(6x-5)=0$

Ans: D. 6x − 5

8 0

4 years ago

Read 2 more answers