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Novosadov [1.4K]
3 years ago
12

Find the missing side of this triangle

Mathematics
1 answer:
Taya2010 [7]3 years ago
4 0

Answer:

5*\sqrt{3}

Step-by-step explanation:

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2. What is the experimental probability of rolling a 4
boyakko [2]

Answer:

1. 40%

2. The theoretical probability is 3% greater than the experimental probability.

Step-by-step explanation:

We are informed that a number cube is rolled 20 times and the number 4 is rolled 8 times. The experimental probability of rolling a 4 is;

(the number of times a 4 was rolled)/(total number of rolls)

8/20 = 0.4

0.4*100 = 40%

The experimental probability of obtaining at least one tails, one or more tails, is represented in mathematical notation as;

P(HT or TH or TT)

The above events are mutually exclusive, thus;

P(HT or TH or TT) = P(HT) + P(TH) + P( TT)

                               = (22+34+16)/(28+22+34+16)  

                               = 0.72 = 72%

On the other hand, the theoretical probability of obtaining at least one tails,

P(HT or TH or TT) = 3/4

                              = 75%

This is because there is at least one tail in 3 out of 4 possible outcomes.

Therefore, it is true to say that the theoretical probability is 3% greater than the experimental probability.

6 0
3 years ago
Read 2 more answers
What percent of 143 is 95.1?
Aloiza [94]

Answer:

66.5%

Step-by-step explanation:

95.1/143*100=66.5%

4 0
3 years ago
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Find the exact value of the expressions
timama [110]

Answer:

here is your correct answer and listen question no four option are incorrect

4 0
3 years ago
Mr. Ketchum collets Pokémon cards. He purchases a rare charizard Pokémon card for $525. Research shows this card value will incr
e-lub [12.9K]

Answer:

18.37500

Step-by-step explanation:

Here You Go! Hope It Helps Bud

5 0
2 years ago
Which piece of additional information can be used to prove △CEA ~ △CDB?
Slav-nsk [51]

<u>Answer-</u>

<em>The correct answer is</em>

<em>∠BDC and ∠AED are right angles</em>

<u>Solution-</u>

In the ΔCEA and ΔCDB,

m\angle BCD=m\angle ACE

As this common to both of the triangle.

If ∠BDC and ∠AED are right angles, then m\angle E=90=m\angle D

Now as

∠BCD = ∠ACE and ∠BDC = ∠AED,

∠DBC and ∠EAC will be same. (as sum of 3 angles in a triangle is 180°)

Then, ΔCEA ≈ ΔCDB

Therefore, additional information can be used to prove ΔCEA ≈ ΔCDB is ∠BDC and ∠AED are right angles.


5 0
3 years ago
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