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natita [175]
2 years ago
8

X+X+(60% of X)=180 Ez points plus brainliest

Mathematics
1 answer:
JulsSmile [24]2 years ago
3 0

Answer:

x = 900/ 10 + 3fo

Step-by-step explanation:

Move all terms to the left side and set equal to zero. Then set each factor equal to zero.

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Using the bijection rule to count binary strings with even parity.
AleksandrR [38]

Answer:

Lets denote c the concatenation of strings. For a binary string <em>a</em> in B9, we define the element f(a) in E10 this way:

  • f(a) = a c {1} if a has an odd number of 1's
  • f(a) = a c {0} if a has an even number of 1's

Step-by-step explanation:

To show that the function f defined above is a bijective function, we need to prove that f is well defined, injective and surjective.

f   is well defined:

To see this, we need to show that f sends elements fromo b9 to elements of E10. first note that f(a) has 1 more binary integer than a, thus, it has 10. if a has an even number of 1's, then f(a) also has an even number because a 0 was added. On the other hand, if a has an odd number of 1's, then f(a) has one more 1, as a consecuence it will have an even number of 1's. This shows that, independently of the case, f(a) is an element of E10. Thus, f is well defined.

f is injective (or one on one):

If a and b are 2 different binary strings, then f(a) and f(b) will also be different because the first 9 elements of f(a) form a and the first elements of f(b) form b, thus f(a) is different from f(b). This proves that f in injective.

f is surjective:

Let y be an element of E10, Let x be the first 9 elements of y, then f(x) = y:

  • If x has an even number of 1's, then the last digit of y has to be 0, and f(x) = x c {0} = y
  • If x has an odd number of 1's, then the last digit of y has to be a 1, otherwise it wont be an element of E10, and f(x) = x c {1} = y

This shows that f is well defined from B9 to E10, injective, and surjective, thus it is a bijection.

3 0
3 years ago
Line parallel to y=2x has a slope of ?
loris [4]

In order to find the slope of a line parallel to this one, we must be familiar with the slope/intercept form, which is y= mx + b. M would be the slope. Therefore this line has a slope of 2. Parallel lines have the same slope, therefore<em> a line parallel to y=2x has a slope of </em><em>2</em><em>. </em>

7 0
3 years ago
Read 2 more answers
Match each function formula with the corresponding transformation of the parent function y = (x - 1)2 1. y = - (x - 1)2 Reflecte
lawyer [7]

Answer:

  1. y = -(x-1)² . . . . reflected over the x-axis
  2. y = (x-1)² +1 . . . . translated up by 1 unit
  3. y = (x+1)² . . . . reflected over the y-axis
  4. y = (x-2)² . . . . translated right by 1 unit
  5. y = (x-1)² -3 . . . . translated down by 3 units
  6. y = (x+3)² . . . . translated left by 4 units

Step-by-step explanation:

Since you have studied transformations, you are familiar with the effect of different modifications of the parent function:

  • f(x-a) . . . translates right by "a" units
  • f(x) +a . . . translates up by "a" units
  • a·f(x) . . . vertically scales by a factor of "a". When a < 0, reflects across the x-axis
  • f(ax) . . . horizontally compresses by a factor of "a". When a < 0, reflects across the y-axis.

Note that in the given list of transformed functions, there is one that is (x+1)². This is equivalent to both f(x+2) and to f(-x). The latter is a little harder to see, until we realize that (-x-1)² = (x+1)². That is, this transformed function can be considered to be either a translation of (x-1)² left by 2 units, or a reflection over the y-axis.

8 0
3 years ago
Pleeeease help me! True or false
zloy xaker [14]
False, since it we substitute x = 4 into the equation we get y = -4 + 3 = -1
8 0
3 years ago
Evaluate 4a^0 where a = -2
Paul [167]

Answer:

4a^0 = 4 \times 1 = 4

3 0
2 years ago
Read 2 more answers
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