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3 years ago

A. What is the circumference of the

Mathematics

1 answer:

erik [133]3 years ago

6 0

Answer:

a) 94.2 cm

b) 78.5%

Step-by-step explanation:

a) since the square side = 30 cm

it means the diameter = 30 cm

then circumference of the largest circle that can be cut = 3.14×30 = 94.2 cm

b) the perimeter of the square = 30×4 = 120

94.2 for 120

x% for 100%

x = (100×94.2)/120 = 9420/120 = 942/12 = 78.5%

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An older person is 8 years older than seven times the age of a younger person. The sum of their ages is 32. What are their ages?

tatiyna

Answer:

there ages are 29 and 3 years old

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2 years ago

Find the percent of decrease from 340 to 260. Round to the nearest tenth of a percent, if necessary. A.) 23.5% B.) 130.8% C.) 30

Ad libitum [116K]

Answer: A) 23.5%
Explanation: 340-260= 80
80/340=0.2352x100=23.5

3 0

3 years ago

Find the number of real zeros of

Amiraneli [1.4K]

Answer:

Step-by-step explanation:

Using the determinant to determine the type of zeros

Given

f(x) = ax² + bx + c ( a ≠ 0 ) ← in standard form, then the discriminant is

Δ = b² - 4ac

• If b² - 4ac > 0 then 2 real and distinct zeros

• If b² - 4ac = 0 then 2 real and equal zeros

• If b² - 4ac < 0 then 2 complex zeros

Given

f(x) = (x - 1)² + 1 ← expand factor and simplify

= x² - 2x + 1 + 1

= x² - 2x + 2 ← in standard form

with a = 1, b = - 2, c = 2, then

b² - 4ac = (- 2)² - (4 × 1 × 2) = 4 - 8 = - 4

Since b² - 4ac < 0 then the zeros are complex

Thus P(x) has no real zeros

6 0

3 years ago

Please answer this if you can tysm

olasank [31]

Answer:

c because you multiply by pie which is 3.14 and that times 10 is 31.4

3 0

3 years ago

Read 2 more answers

According to the article "Characterizing the Severity and Risk of Drought in the Poudre River, Colorado" (J. of Water Res. Plann

mihalych1998 [28]

Answer:

(a) P (Y = 3) = 0.0844, P (Y ≤ 3) = 0.8780

(b) The probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

Step-by-step explanation:

The random variable Y is defined as the number of consecutive time intervals in which the water supply remains below a critical value y₀.

The random variable Y follows a Geometric distribution with parameter p = 0.409.

The probability mass function of a Geometric distribution is:

$P(Y=y)=(1-p)^{y}p;\ y=0,12...$

(a)

Compute the probability that a drought lasts exactly 3 intervals as follows:

$P(Y=3)=(1-0.409)^{3}\times 0.409=0.0844279\approx0.0844$

Thus, the probability that a drought lasts exactly 3 intervals is 0.0844.

Compute the probability that a drought lasts at most 3 intervals as follows:

P (Y ≤ 3) = P (Y = 0) + P (Y = 1) + P (Y = 2) + P (Y = 3)

$=(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409+(1-0.409)^{2}\times 0.409\\+(1-0.409)^{3}\times 0.409\\=0.409+0.2417+0.1429+0.0844\\=0.8780$

Thus, the probability that a drought lasts at most 3 intervals is 0.8780.

(b)

Compute the mean of the random variable Y as follows:

$\mu=\frac{1-p}{p}=\frac{1-0.409}{0.409}=1.445$

Compute the standard deviation of the random variable Y as follows:

$\sigma=\sqrt{\frac{1-p}{p^{2}}}=\sqrt{\frac{1-0.409}{(0.409)^{2}}}=1.88$

The probability that the length of a drought exceeds its mean value by at least one standard deviation is:

P (Y ≥ μ + σ) = P (Y ≥ 1.445 + 1.88)

= P (Y ≥ 3.325)

= P (Y ≥ 3)

= 1 - P (Y < 3)

= 1 - P (X = 0) - P (X = 1) - P (X = 2)

$=1-[(1-0.409)^{0}\times 0.409+(1-0.409)^{1}\times 0.409\\+(1-0.409)^{2}\times 0.409]\\=1-[0.409+0.2417+0.1429]\\=0.2064$

Thus, the probability that the length of a drought exceeds its mean value by at least one standard deviation is 0.2064.

6 0

3 years ago