What is the upper quartile, Q3, of the following data set? 54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41
scZoUnD [109]
The original data set is
{<span>54, 53, 46, 60, 62, 70, 43, 67, 48, 65, 55, 38, 52, 56, 41}
Sort the data values from smallest to largest to get
</span><span>{38, 41, 43, 46, 48, 52, 53, 54, 55, 56, 60, 62, 65, 67, 70}
</span>
Now find the middle most value. This is the value in the 8th slot. The first 7 values are below the median. The 8th value is the median itself. The next 7 values are above the median.
The value in the 8th slot is 54, so this is the median
Divide the sorted data set into two lists. I'll call them L and U
L = {<span>38, 41, 43, 46, 48, 52, 53}
U = {</span><span>55, 56, 60, 62, 65, 67, 70}
they each have 7 items. The list L is the lower half of the sorted data and U is the upper half. The split happens at the original median (54).
Q3 will be equal to the median of the list U
The median of U = </span>{<span>55, 56, 60, 62, 65, 67, 70} is 62 since it's the middle most value.
Therefore, Q3 = 62
Answer: 62</span>
im not sure how to explain it, but i know its b
Answer:
144π
Step-by-step explanation:
we need the radisu
circumference formula: 2πr
2πr=24π
12=r
area formula:
πr²
12²π= 144π
Divide 405 by 6 which is 67.5
So 67.5 per hour but it wants minutes
So divide 67.5 by 60 (minutes in an hour) and you’ll get 1.125 pages per minute
Hello from MrBillDoesMath!
Answer:
-9 sqrt(5)
Discussion:
-2 sqrt(20) - sqrt(125) =
-2 *2 sqrt(5) - sqrt(125)= as 20 = 4* 5
-4sqrt(5)- 5 sqrt(5) = as 125 = 25 *5
(-4 -5) sqrt(5) =
-9 sqrt(5)
Thank you,
MrB
