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3 years ago

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A concert ticket that originally cost $46.50 is on sale for $38.75. What is the percent of decrease, rounded to the nearest tent

h?

1 answer:

Arturiano [62]3 years ago

5 0

You subtract 38.75 from 46.5, which is 7.75. 7.75/46.5=about .16666, or 16.7 percent.

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Which of the following statement is incorrect? .

Nuetrik [128]

Answer:

b) Commutative property is true for subtraction of Rational numbers

Step-by-step explanation:

Option B is incorrect.
Commutative property is not true for subtraction of Rational numbers .

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Malcom is filling bags with rice . He starts with a 5 1/4 pound container of rice and fills each bag with 5/8 pounds of rice . H

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Answer:

Malcolm would fill 8 bags of rice.

Step-by-step explanation:

The size of the container of rice = 5 $\frac{1}{4}$ pounds = $\frac{21}{4}$ pounds.

Each bag of rice has a capacity of $\frac{5}{8}$ pounds.

The number of bags of rice that Malcolm fills = $\frac{total quantity of rice}{capacity of each bag}$

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Maksim231197 [3]

Answer:

See below

Step-by-step explanation:

I will denote your new addition by +', and your new scalar multiplication by * to distinguish them from the usual operations.

1) x+'y=y+'x. Yes: Let x=[a,b] and y=[c,d]. Then x+'y=[0,b+d]=[0,d+b]=y+'x

2) (x+'y)+'z=x+'(y+'z). Yes: Let x=[a,b], y=[c,d], z=[e,f]

Then (x+'y)+'z=[0,b+d]+'[e,f]=[0,(b+d)+f]=[0,b+(d+f)]=[a,b]+'[0,d+f]=x+'(y+'z)

3) There exists an element 0 in V such that x+'0=x for each x in V: No

Take x=[1,0]. Then x+'[a,b]=[0,b]≠[1,0], so 0=[a,b] does not exist (no choice of 0 works for this x)

4) For each x in V, there exists an element -x in V such that x+'(-x)=0. Yes (if 0=[0,0])

Given x=[a,b], take -x=[a,-b]. Then x+'(-x)=[0,b-b]=[0,0]=0.

5) *k(x+y)=(*kx)+'(*ky) for each scalar k and any x and y in V. Yes

Let x=[a,b] and y=[c,d]. Then *k(x+'y)=*k[0,b+d]=[0,k(b+d)]=[0,kb]+[0,kd]=*kx+*ky.

6) (s+t)*x=(*sx)+(*tx) for any scalars s and t and any x in V. Yes

Let x=[a,b]. Then (s+t)*x=[0,(s+t)b]=[0,sb]+[0,tb]=*sx+*tx

7) (*s)(*tx)=*(st)x for any scalars s and t and any x in V. Yes

Let x=[a,b]. Then (*s)(*tx)=*s[0,tb]=[0,stb]=*(st)x

8) *1x=x for all x in V. No

*1[1,2]=[0,2]≠[1,2]

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3 years ago