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hjlf
3 years ago
5

Due Today!!! Please Help!!!

Mathematics
1 answer:
Hatshy [7]3 years ago
6 0

Answer:

x=59

Step-by-step explanation:

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I need help with this
Stells [14]

Answer:

AB = 21

Step-by-step explanation:

So we have two triangles (AEB and ADC), and they're similar by AA

Now, you can find the ratio of similitude by checking AE/AD which is 14/26 = 7/13

AB/AC = 7/13

Take AB as x aight

x/x+18 = 7/13

x=21

5 0
2 years ago
What is the number in scientific notation? 409,200,000,000
gavmur [86]
4.092 x 10 to the 11th power
7 0
3 years ago
Read 2 more answers
How do I solve this problem
Rufina [12.5K]
X+5+2x-2+90=180. combine like terms and solve like a normal algebra problem to find x. if you need to find the answer for a certain angle, plug in the value you got for x into one of the angle equations
8 0
3 years ago
Stan's Sweater Superstore has a 30% off sale. This week only, everything in the store is marked down an additional 10% off the s
evablogger [386]

Answer:

$30

Step-by-step explanation:

30 % + 10 % = 40 %

40 % of $50 = $20

%50 - $20 = $30

8 0
3 years ago
What is the equation of the line that represents the horizontal asymptote of the function f(x)=25,000(1+0.025)^(x)?
posledela

Answer:

The answer is below

Step-by-step explanation:

The horizontal asymptote of a function f(x) is gotten by finding the limit as x ⇒ ∞ or x ⇒ -∞. If the limit gives you a finite value, then your asymptote is at that point.

\lim_{x \to \infty} f(x)=A\\\\or\\\\ \lim_{x \to -\infty} f(x)=A\\\\where\ A\ is\ a\ finite\ value.\\\\Given\ that \ f(x) =25000(1+0.025)^x\\\\ \lim_{x \to \infty} f(x)= \lim_{x \to \infty} [25000(1+0.025)^x]= \lim_{x \to \infty} [25000(1.025)^x]\\=25000 \lim_{x \to \infty} [(1.025)^x]=25000(\infty)=\infty\\\\ \lim_{x \to -\infty} f(x)= \lim_{x \to -\infty} [25000(1+0.025)^x]= \lim_{x \to -\infty} [25000(1.025)^x]\\=25000 \lim_{x \to -\infty} [(1.025)^x]=25000(0)=0\\\\

Since\  \lim_{x \to -\infty} f(x)=0\ is\ a\ finite\ value,hence:\\\\Hence\ the\ horizontal\ asymtotes\ is\ at\ y=0

5 0
3 years ago
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