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MrRa [10]
2 years ago
14

What is the y-intercept of the graph of y = 4^x-2?

Mathematics
2 answers:
raketka [301]2 years ago
6 0

y =  {4}^{x}  - 2 \\ for \: y \: intercept \: x \: s \\ is \: 0 \\ y =  {4}^{0} - 2 \\ y = 1 - 2 \\ y =  - 1 \\

Y intercept : (0,-1)

Hope it helps

please give brainliest

mixas84 [53]2 years ago
5 0

Answer: Hope this helps you.

-2

Step-by-step explanation:

y = mx+b (B is y-int)

y = 4^x-2

-2 is clearly replacing the b (y-int) meaning b, the y-int, is -2

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X + ky = 1
Marina CMI [18]
X + k y = 1
k x + y = 1  / * ( - k )
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      x + k y = 1
- k² x - k y = - k
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x - k² x = 1 - k
x ( 1 - k² ) = 1 - k
x = ( 1 - k ) / ( 1 - k² ) = ( 1 - k ) / ( 1 - k ) ( 1 + k )
y = 1 - k( 1 - k )/( 1 - k² )
y = ( 1 - k ) / ( 1 - k² ) = ( 1 - k ) / ( 1 - k ) ( 1 + k )
a ) For  k = - 1 this system has no solution.
b ) For k ≠ - 1 and k ≠ 1, the system has unique solution:
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3 0
3 years ago
Ebi, Jose, Derell, and Asami measured their heights. Ebi's height was 2.5 cm greater than Jose's height. Jose's height was 3.1 c
irga5000 [103]
Start with assigning each person with a variable to represent their height

Ebi: e
Jose: j
Derell: d
Asami: a

Ebi'd height was 2.5 cm greater than Jose's height

j + 2.5 = e

Jose's height was 3.1 cm greater than Derell's

d + 3.1 = j

Derell's height is 0.4 cm less than Asami's height

a - 0.4 = d

Ebi is 162.5 cm tall

e = 162.5

So, plug in 162.5 into any of the above equations were there is a variable of e

j + 2.5 = e

j + 2.5 = 162.5

Subtract 2.5 from both sides of the equation

j = 160 cm

Jose's height is 160 cm

Now, plug in 160 into any of the above equations where there is a j

d + 3.1 = j

d + 3.1 = 160

Subtract 3.1 from both sides of the equation 

d = 156.9 cm

Derell's height 156.9 cm

so, plug in 156.9 into any of the above equations where there is a d

a - 0.4 = d

a - 0.4 = 156.9

Add 0.4 on both sides of the equation

a = 157.3 cm

Asami's height is 157.3 cm



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lutik1710 [3]
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