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2 years ago

Help!!!!!! Find x and y so the quadrilateral is a parallelogram.

Mathematics

1 answer:

iren [92.7K]2 years ago

3 0

Answer:

Conclusion:

The value of x = 7

The value of y = 4

Step-by-step explanation:

Given

The parallelogram PQRS

We know that the diagonals of a parallelogram bisect each other.

Therefore,

RT = TP

Given RT = x and TP = 5x-28, so

x = 5x-28

5x = x+28

5x-x = 28

4x = 28

divide boh sides by 4

4x/4 = 28/4

x = 7

Thus, the value of x = 7

Similarly,

QT = TS

Given QT = 5y and TS = 2y+12, so

5y = 2y+12

5y-2y = 12

3y = 12

divide both sides by 3

3y/3 = 12/3

y = 4

Thus, the value of y = 4

Conclusion:

The value of x = 7

The value of y = 4

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Archy [21]

Answer:

249.6

Step-by-step explanation

There are 4 identical equilateral triangle,

we can find the area of one and multiply by 4

area of triangle = $\frac{1}{2} *base*hight=\frac{1}{2}*12*10.4=62.4$

now 62.4*4 = 249.6

6 0

3 years ago

I need help with this

olga2289 [7]

Answer:

x = 24.52

Step-by-step explanation:

Since this is a right triangle, use Pythagorean Theorem to solve for the hypotenuse.

Pythagorean Theorem: a² + b² = c²

24² + 5² = x²

576 + 25 = x²

601 = x²

√601 = x

4 0

3 years ago

How much would $500 invested at 7% interest compounded continuously be worth after 4 years? Round your answer to the nearest cen

Greeley [361]

Hi I hope this helps;

3 0

3 years ago

The area of a rectangle is 42 square millimeters. The length is 7 millimeters. What is the perimeter of the rectangle?

Aleks [24]

Answer:

26 mm

Step-by-step explanation:

A=wl= 42 mm²

l=7, w= 42/7= 6 mm

P=2(l+w)= 2(7+6)= 26 mm

8 0

3 years ago

6-10 divide, another onee thank you!!

eduard

Answers:

10.) $\displaystyle \pm{5}$

9.) $\displaystyle 1\frac{1}{2}$

8.) $\displaystyle \pm{1\frac{1}{2}}$

7.) $\displaystyle \pm{1\frac{1}{2}}$

6.) $\displaystyle \pm{\frac{1}{2}}$

Step-by-step explanations:

10.) $\displaystyle \frac{\sqrt{200}}{\sqrt{8}} \hookrightarrow \sqrt{25} \hookrightarrow \frac{\pm{10\sqrt{2}}}{\pm{2\sqrt{2}}} \\ \\ \boxed{\pm{5}}$

9.) $\displaystyle \frac{\sqrt[3]{135}}{\sqrt[3]{40}} \hookrightarrow \sqrt[3]{3\frac{3}{8}} \hookrightarrow \frac{3\sqrt[3]{5}}{2\sqrt[3]{5}} \\ \\ \boxed{1\frac{1}{2}}$

8.) $\displaystyle \frac{\sqrt[4]{162}}{\sqrt[4]{32}} \hookrightarrow \sqrt[4]{5\frac{1}{16}} \hookrightarrow \frac{\pm{3\sqrt[4]{2}}}{\pm{2\sqrt[4]{2}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}$

7.) $\displaystyle \frac{\sqrt{63}}{\sqrt{28}} \hookrightarrow \sqrt{2\frac{1}{4}} \hookrightarrow \frac{\pm{3\sqrt{7}}}{\pm{2\sqrt{7}}} \\ \\ \boxed{\pm{1\frac{1}{2}}}$

6.) $\displaystyle \frac{\sqrt{12}}{\sqrt{48}} \hookrightarrow \sqrt{\frac{1}{4}} \hookrightarrow \frac{\pm{2\sqrt{3}}}{\pm{4\sqrt{3}}} \\ \\ \boxed{\pm{\frac{1}{2}}}$

I am joyous to assist you at any time.

5 0

2 years ago