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Len [333]
3 years ago
7

What is -7 to the second power

Mathematics
2 answers:
Paha777 [63]3 years ago
8 0

Answer:

+49

Step-by-step explanation:

-7 x -7 = +49 because the negatives cancel out, resulting in a positive

valkas [14]3 years ago
3 0

Answer:

49

Step-by-step explanation:

-7 multiplied by -7 would be 49

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Help on a,b, and d please!
Umnica [9.8K]
That's too much. you should just put it separate. most won't want to answer.
3 0
3 years ago
£980 is divided between Caroline, Sarah & Gavyn so that Caroline gets twice as much as Sarah, and Sarah gets three times as
Nitella [24]

Sarah has received £ 294

<u><em>Solution:</em></u>

Given that £980 is divided between Caroline, Sarah & Gavyn

Let "c" be the amount received by caroline

Let "s" be the amount received by sarah

Let "g" be the amount received by gavyn

<em><u>Caroline gets twice as much as Sarah</u></em>

amount received by caroline = twice as much as Sarah

amount received by caroline = 2(amount received by sarah)

c = 2s ---- eqn 1

<em><u>Sarah gets three times as much as Gavyn</u></em>

amount received by sarah = three times as much as Gavyn

amount received by sarah = 3(amount received by gavyn)

s = 3g ------- eqn 2

Given that total amount is 980

c + s + g = 980 --- eqn 3

<em><u>Let us solve eqn 1, 2, 3 to get values of "c" "s" "g"</u></em>

From eqn 2,

g = \frac{s}{3}  --- eqn 4

Substitute eqn 1 and eqn 4 in eqn 3

2s + s + \frac{s}{3} = 980\\\\\frac{6s + 3s + s}{3} = 980\\\\6s + 3s + s = 980 \times 3\\\\10s = 2940\\\\s = 294

Thus sarah has received £ 294

7 0
3 years ago
Which values are solutions 4x greater than or equal to 35
Mamont248 [21]

Answer:

\frac{5}{1/2}, 12, \frac{8}{3/4}, 10

Step-by-step explanation:

4x\geq 35

x \geq \frac{35}{4}

x \geq 8 \frac{3}{4}

so

\frac{5}{1/2} = 10

12

\frac{8}{3/4} = 10.66

and 10

Because saying 5 over 1/2 is saying 5 divided by 1/2 which is the same as saying 5 * 2

8 over 3/4 is 8 divided by 3/4 which is 8 * 1.33.

A fraction is division. If you mean 5 and 1/2 as well as 8 and 3/4 then remove 5 and 1/2 from the answer.

6 0
3 years ago
The area of a circle is 616 m square find the radius 5 equals to 22/7 ​
astra-53 [7]

Step-by-step explanation:

here \: is \: your \: solution :  -  \\  \\ GIVEN  \:  \: -:- \\  \\  =  >  \: area \: of \: circle \:  = 616 \: m {}^{2}  \\  \\ \ =  > pi = 22  \div 7 \\  \\  =  > we \: need \: to \: find \: radius \:  \\  \\  =  > area \: of \: circle \:  = \pi \: r {}^{2}  \\  \\  =  >  \: \pi \: r {}^{2}  = 616 \: m {}^{2}  \\  \\  =  >  \: r {}^{2}  \times (22 \div 7) = 616 \\  \\  =  >  \: r {}^{2}  =( 616 \times 7) \div 22 \\  \\  =  >  \: r {  }^{2}  = 4312 \div 22 \\  \\  =  > r {}^{2}  = 196 \\  \\  =  >  \: r =  \sqrt{196}  \\  \\  =  >  \: r = 14 \: \:   \: (ANSWER✓✓✓) \\  \\ HOPE \:  IT \:  HELPS \:  YOU \: (◕ᴗ◕✿)

7 0
2 years ago
I need help ASAP! Can anyone please check my work?
STALIN [3.7K]

A = event the person got the class they wanted

B = event the person is on the honor roll

P(A) = (number who got the class they wanted)/(number total)

P(A) = 379/500

P(A) = 0.758

There's a 75.8% chance someone will get the class they want

Let's see if being on the honor roll changes the probability we just found

So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).

---------------

A and B = someone got the class they want and they're on the honor roll

P(A and B) = 64/500

P(A and B) = 0.128

P(B) = 144/500

P(B) = 0.288

P(A | B) = P(A and B)/P(B)

P(A | B) = 0.128/0.288

P(A | B) = 0.44 approximately

This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.

Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.

Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.

8 0
3 years ago
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