Answer:
ΔSTR is similar to ΔRTQ
Step-by-step explanation:
Given QRS is a right angled triangle. we have to find the similarity statement ΔSTR ~ Δ__
Let ∠S=x
In ΔSTR, by angle sum property
∠S+∠STR+∠SRT=180°
⇒ ∠SRT=90°-x
In ΔSRQ, by angle sum property
∠S+∠R+∠Q=180°
⇒ ∠Q=90°-x
In ΔSTR and ΔRTQ
∠SRT=∠Q=90°-x (proved above)
∠STR=∠RTQ (each 90°)
RT=RT (common)
Hence, by AAS rule ΔSTR≅ΔRTQ
∴ ΔSTR is similar to ΔRTQ
Option 4 is correct.
C because think it is the Answer
Answer:
0.53846153846
Step-by-step explanation:
if you divide 0.07 by 0.13 you get 0.53846153846
Answer:
1
Step-by-step explanation:
