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Sum f(k)=4k-10 for k=1 to 18.
We sum each term separately and add the sums.
![\sum_1^{18}4k=4\sum_1^{18}k=4[18(1+18)/2]=4*9*19=684](https://tex.z-dn.net/?f=%5Csum_1%5E%7B18%7D4k%3D4%5Csum_1%5E%7B18%7Dk%3D4%5B18%281%2B18%29%2F2%5D%3D4%2A9%2A19%3D684)
Therefore the required sum is 684-180=504
We sum each term separately and add the sums.
Therefore the required sum is 684-180=504