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kolezko [41]
2 years ago
9

Mr. Kershner is a school nurse. He uses, on average, 24 self-adhesive bandages during each spring month: March, April, and May.

He also knows that in June there are several field days and he will need 4 times the number of bandages for that month.
If the bandages cost 3 cents each, what is his total cost for March through June?
Mathematics
1 answer:
icang [17]2 years ago
6 0

Answer:

oop lol why did no one answer this I am having trouble on this too...

When I get the answer ill edit this and put it in!

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angle 0 is in quadrant 1 with sin0 = 2/5. Use the Pythagorean identity, sin^2 0 + cos^2 0 = 1, to calculate the value of cos0 as
Gwar [14]
We know that
sin²x+cos²x=1
so 
clear cos x
cos x=(+/-)√[1-sin²x]

in this problem
<span>Angle 0 is in quadrant 1 -----> cos o and sin o are positive
</span>sin o=2/5
cos x=√[1-(2/5)²]----> cos o=√[1-4/25]----> cos o=√[21/25]---> cos o=√21/5

the answer is
cos o=√21/5

7 0
2 years ago
Three consecutive integers have a sum of 234. What are the three integers
likoan [24]
234 - 3 = 231
231 : 3 = 77
77 + 1 =78
78 + 1 = 79
------------------------
77   78   79
77+78+79= 234
7 0
3 years ago
Help will give brainliest
I am Lyosha [343]

Answer:

the answer is y = x + 1

have a good day :3

7 0
2 years ago
How long does it take to drive 272 miles going 68mph
DedPeter [7]
<span>272mi/68mi/hr= 4 hr

Example:
Calculate the acceleration of a boat that has been cruising at 15 m/s but speeds up to 45 m/s in about 6 seconds. Don’t forget your units, m/s2. In order to calculate the acceleration of the boat we first have to identify the suited formula for acceleration in this scenario. </span>

<span>Hence, a = vf – vi / t. Vi = 15 m/s Vf = 45 m/s T = 6 seconds   </span>

<span>Solution: </span>
<span>A = 45 m/s – 15m/s / 6s </span>
A = 5m/s^2<span>
</span>

7 0
3 years ago
Read 2 more answers
Find the length of the missing sides in the triangle
Alex

Answer:

b. \displaystyle x ≈ 9,9, y = 7

Step-by-step explanation:

In a 45°-45°-90° triangle, both legs are congruent \displaystyle [x],whereas the hypotenuse is represented by \displaystyle x\sqrt{2}. So, evaluate:

\displaystyle hypotenuse \hookleftarrow x\sqrt{2} \\ \\ 9,8994949366... = \boxed{7\sqrt{2}}

Therefore, you have this:

\displaystyle 9,9 ≈ x

I am joyous to assist you at any time.

4 0
1 year ago
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