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2 years ago

What's the mean, median, and mode of 3, 5, 1, 5, 1, 1, 2, 3, 15.

Mathematics

2 answers:

12345 [234]2 years ago

6 0

<h2>Answer:</h2><h3>mean = 4</h3>

<h3>Median = 3</h3>

<h2>Step-by-step explanation:</h2>

<h3>first let’s arrange the numbers in ascending order:</h3>

<h3>The median is the number that’s comes in the middle of the data set: median = 3 ( the fifth number in the data set)</h3><h3 /><h3>1 , 1 , 1 , 2 , 3, 3 , 5 , 5 , 15</h3>

<h3>The mode is the number that repeats the most ⇒ mode = 1 (repeated 3 times)</h3>

<h3>the mean= sum of total number/total number of occurence</h3><h3>mean = 1+1+1+2+3+3+5+5+15/9</h3><h3 /><h3>mean= 36/9= 4</h3>

lara [203]2 years ago

4 0

<h3><em>Answer:</em></h3>

<em>Median = 3</em>

Step-by-step explanation:

first let’s arrange the numbers from least to highest:

1 , 1 , 1 , 2 , 3 , 3 , 5 , 5 , 15

=====================

The median is the number that’s comes in the middle of the data set ⇒ median = 3 ( the fifth number in the data set)

1 , 1 , 1 , 2 , <u>3</u>, 3 , 5 , 5 , 15

________________________

The mode is the number that repeats the most ⇒ mode = 1 (repeated 3 times)

____________________________________

$\text{the mean} =\frac{1+1+1+2+3+3+5+5+15}{9} = \frac{36}{9}=4$

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Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering p

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Answer:

1.778 times more or 16/9 times more

Step-by-step explanation:

Given:

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- Mirror 2: D_2 = 6"

Find:

Compare the light gathering power of an 8" primary mirror with a 6" primary mirror. The 8" mirror has how much light gathering power?

Solution:

- The light gathering power of a mirror (LGP) is proportional to the Area of the objects:

LGP ∝ A

- Whereas, Area is proportional to the squared of the diameter i.e an area of a circle:

A ∝ D^2

- Hence, LGP ∝ D^2

- Now compare the two diameters given:

LGP_1 ∝ (D_1)^2

LGP ∝ (D_2)^2

- Take a ratio of both:

LGP_1/LGP_2 ∝ (D_1)^2 / (D_2)^2

- Plug in the values:

LGP_1/LGP_2 ∝ (8)^2 / (6)^2

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3 years ago

Please helped this is for my math final.

hammer [34]

Answer:

[-8,8]

Step-by-step explanation:

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2 years ago

Find the slope intercept form for the equation of the line which passes through the point (-4,-14) and has a slope of 1

Fudgin [204]

Use point slope form to answer this
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3 years ago

Find three positive numbers whose sum is 140 and whose product is a maximum. (Enter your answers as a comma-separated list.)

Paladinen [302]

Answer:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

Step-by-step explanation:

Let the numbers be $x, y\ and\ z.$

Such that:

$x + y + z = 140$

Make z the subject

$z = 140 -x - y$

For their product to be maximum, we have:

$f(x,y,z) = xyz$

Substitute $z = 140 -x - y$ in $f(x,y,z) = xyz$

$f(x,y) = xy(140 - x - y)$

Open bracket

$f(x,y) = 140xy - x^2y - xy^2$

Differentiate w.r.t x and y

$f_x=140y - 2xy - y^2$

$f_y=140x - x^2 - 2xy$

Since the products are maximum, then $f_x = f_y = 0$

For $f_x=140y - 2xy - y^2$

$140y - 2xy - y^2 = 0$

Factorize:

$y(140 - 2x - y) = 0$

Split

$y = 0\ or\ 140 - 2x - y = 0$

Make y the subject

$y = 0\ or\ y = 140 - 2x$

For $f_y=140x - x^2 - 2xy$

$140x - x^2 - 2xy = 0$

---------------------------------------------------

Substitute y = 0

$140x - x^2 -2x*0 = 0$

$140x - x^2 = 0$

Factorize

$x(140 - x)= 0$

$x = 0\ or\ 140-x = 0$

$x = 0\ or\ x = 140$

---------------------------------------------------

Substitute $y = 140 - 2x$

$140x - x^2 - 2xy = 0$

$140x - x^2 - 2x(140 - 2x) = 0$

$140x - x^2 - 280x + 4x^2 = 0$

Re-arrange

$4x^2 -x^2 +140x - 280x = 0$

$3x^2 -140x = 0$

Factor x out

$x(3x - 140) = 0$

Divide through by x

$3x - 140 = 0$

$3x = 140$

$x = \frac{140}{3}$

Recall that: $y = 140 - 2x$

$y = 140 - 2 * \frac{140}{3}$

$y = 140 - \frac{280}{3}$

Take LCM

$y = \frac{140*3-280}{3}$

$y = \frac{140}{3}$

Recall that:

$z = 140 -x - y$

$z = 140 - \frac{140}{3} - \frac{140}{3}$

Take LCM

$z = \frac{3 * 140- 140 - 140}{3}$

$z = \frac{140}{3}$

Hence, the numbers are:

$\frac{140}{3}, \frac{140}{3}, \frac{140}{3}$

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2 years ago

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When there's a strong positive, the points are: B. Close together.

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On a scatter plot, if the data points are close together along the trend line sloping upwards, it means there's a strong positive correlation.
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Therefore, when there's a strong positive, the points are: B. Close together.

Learn more about strong positive relationship on:

brainly.com/question/15552860

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2 years ago