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2 answers:
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a gradient of a line that is parallel and perpendicular to this line with this gradient of -2
Gradient is the slope
So slope of the line =-2
Slope of parallel line is equal to the slope of the line
So slope of parallel line = -2
Slope of perpendicular line is equal to negative reciprocal of slope of the line
We know slope of line = -2
Negative reciprocal =
So , Slope of perpendicular line=
The equation of the tangent to the curve at the point P(2, -10) is:
y = 8x - 26
We need to find the coordinates of point Q where the slope of the tangent to the curve f(x) must also be 8.
Now we have a quadratic:
which simplifies to:
which factorizes to:(x + 4)(x - 2) = 0
Therefore x = -4, 2.
f(-4) = 48
Therefore the coordinates of Q are (-4, 48).
y = 8x - 26
We need to find the coordinates of point Q where the slope of the tangent to the curve f(x) must also be 8.
Now we have a quadratic:
which simplifies to:
which factorizes to:(x + 4)(x - 2) = 0
Therefore x = -4, 2.
f(-4) = 48
Therefore the coordinates of Q are (-4, 48).