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xz_007 [3.2K]
3 years ago
10

Write the equation for this line in slope-intercept form

Mathematics
2 answers:
dimulka [17.4K]3 years ago
6 0

Answer:

y=x-1

Step-by-step explanation:

g100num [7]3 years ago
4 0

Answer:

y = \frac{2}{3} x - 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 3, - 3) and (x₂, y₂ ) = (3, 1) ← 2 points on the line

m = \frac{1+3}{3+3} = \frac{4}{6} = \frac{2}{3} , then

y = \frac{2}{3} x + c ← is the partial equation

To find c substitute either of the 2 points into the partial equation

Using (3, 1 ) , then

1 = 2 + c ⇒ c = 1 - 2 = - 1

y = \frac{2}{3} x - 1 ← equation of line

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3 years ago
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c

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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4 years ago
Car X weighs 136 pounds more than car Z. Car Y weighs 117 pounds more than car Z. The total weight of all three cars is 9439 pou
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Let x, y and z denote the weighs of car X, car Y and car Z, respectively.

We know that car X weighs 136 more than car Z, this can be express by the equation:

x=z+136

We also know that Y weighs 117 pounds more than car Z, this can be express as:

y=z+117

Finally, we know that the total weight of all the cars is 9439, then we have:

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Hence, we have the system of the equations:

\begin{gathered} x=z+136 \\ y=z+117 \\ z+y+z=9439 \end{gathered}

To solve the system we can plug the values of x and y, given in the first two equations, in the last equation; then we have:

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Now that we have the value of z we plug it in the first two equations to find x and y:

\begin{gathered} x=3062+136=3198 \\ y=3062+117=3179 \end{gathered}

Therefore, car X weighs 3198 pound, car Y weighs 3179 pounds and car Z weighs 3062 pounds.

4 0
1 year ago
32 ten is the same as ?
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32 tens are the same as 320
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4 years ago
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