Step-by-step explanation:
let us give all the quantities in the problem variable names.
x= amount in utility stock
y = amount in electronics stock
c = amount in bond
“The total amount of $200,000 need not be fully invested at any one time.”
becomes
x + y + c ≤ 200, 000,
Also
“The amount invested in the stocks cannot be more than half the total amount invested”
a + b ≤1/2 (total amount invested),
=1/2(x + y + c).
(x+y-c)/2≤0
“The amount invested in the utility stock cannot exceed $40,000”
a ≤ 40, 000
“The amount invested in the bond must be at least $70,000”
c ≥ 70, 000
Putting this all together, our linear optimization problem is:
Maximize z = 1.09x + 1.04y + 1.05c
subject to
x+ y+ c ≤ 200, 000
x/2 +y/2 -c/2 ≤ 0
≤ 40, 000,
c ≥ 70, 000
a ≥ 0, b ≥ 0, c ≥ 0.
Answer:
How are we suppose to answer this on this website?
Step-by-step explanation:
Answer:
option A
12m/s
Step-by-step explanation:
Given in the question,
mass of object = 11kg
kinetic energy possess by = 792 joules
To find the velocity we use formula
v = 
Plug values in the formula
v = 
v = 
v = 
v= 12 m/s
Answer:
Philip
Full name: Phillip Calvin McGraw
28/81 is less than 7/9
28/81 is less than 4/9
The common denominator is 81, so you say 9 can go into 81 nine times, so you multiply 9 by the numerator, so 7/9 is now 63/81 an 4/9 is now 36/81
