The first operation performed while evaluating would be to do the parenthesis
Answer:
Kameryn will have more words typed than Joe when the number of minutes exceeds 34.
Step-by-step explanation:
Let
x -----> the number of minutes
y ----> the total words typed
we know that
<em>Kameryn</em>
-----> equation A
<em>Joe</em>
-----> equation B
Solve the system of equations by substitution
Substitute equation A in equation B and solve for x
That means
For x=34 minutes
The amount of words written by Kameryn and Joe are the same.
therefore
For x > 34 minutes
Kameryn will have more words typed than Joe when the number of minutes exceeds 34.
No because they would each have to cost less than 50 cents for that to be possible and there are 18 flowers.
Find where the expression
x
−
5
x
2
−
25
x
-
5
x
2
-
25
is undefined.
x
=
−
5
,
x
=
5
x
=
-
5
,
x
=
5
Since
x
−
5
x
2
−
25
x
-
5
x
2
-
25
→
→
−
∞
-
∞
as
x
x
→
→
−
5
-
5
from the left and
x
−
5
x
2
−
25
x
-
5
x
2
-
25
→
→
∞
∞
as
x
x
→
→
−
5
-
5
from the right, then
x
=
−
5
x
=
-
5
is a vertical asymptote.
x
=
−
5
x
=
-
5
Consider the rational function
R
(
x
)
=
a
x
n
b
x
m
R
(
x
)
=
a
x
n
b
x
m
where
n
n
is the degree of the numerator and
m
m
is the degree of the denominator.
1. If
n
<
m
n
<
m
, then the x-axis,
y
=
0
y
=
0
, is the horizontal asymptote.
2. If
n
=
m
n
=
m
, then the horizontal asymptote is the line
y
=
a
b
y
=
a
b
.
3. If
n
>
m
n
>
m
, then there is no horizontal asymptote (there is an oblique asymptote).
Find
n
n
and
m
m
.
n
=
1
n
=
1
m
=
2
m
=
2
Since
n
<
m
n
<
m
, the x-axis,
y
=
0
y
=
0
, is the horizontal asymptote.
y
=
0
y
=
0
There is no oblique asymptote because the degree of the numerator is less than or equal to the degree of the denominator.
No Oblique Asymptotes
This is the set of all asymptotes.
Vertical Asymptotes:
x
=
−
5
x
=
-
5
Horizontal Asymptotes:
y
=
0
y
=
0
No Oblique Asymptotes
