Whats the set builder notation of 1,2,4,8,16,32,64
1 answer:
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Answer:
B.
Step-by-step explanation:
First, using two points (0, -4) and (3, 5), find slope:
Slope, m = 3
Next, determine the y-intercept, b.
The y-intercept is the value of y when x = 0. It is the point where the line intercepts the y-axis.
From the graph given, y-intercept, b, is -4.
Substitute b = -4 and m = 3 into .
The equation would be:
✔️
A. True. We see this by taking the highest order term in each factor:
B. True. Again we look at the leading term's degree and coefficient. f(x) behaves like -3x⁶ when x gets large. The degree is even, so as x goes to either ± ∞, x⁶ will make it positive, but multiplying by -3 will make it negative. So on both sides f(x) approaches -∞.
C. False. f(x) = 0 only for x=0, x = 5, and x = -2.
D. False. Part of this we know from the end behavior discussed in part B. On any closed interval, every polynomial is bounded, so that for any x in [-2, 5], f(x) cannot attain every positive real number.
E. True. x = 0 is a root, so f(0) = 0 and the graph of f(x) passes through (0, 0).
F. False. (0, 2) corresponds to x = 0 and f(x) = 2. But f(0) = 0 ≠ 2.
Answer:
<u>Step-by-step explanation:</u>
(1, 2) and (4, -3)
First, find the slope (m):
m =
=
Next, choose ONE of the points and input the point and slope into the Point-Slope formula: y - y₁ = m(x - x₁)
y - 2 = (x - 1)
y - 2 = +
y = +
Then, determine which inequality symbol will result in (-2, 8) being False (since it is not a solution):
y ___ +
8 ___ +
8 ___
8 >
so ≤ makes the statement False
⇒ y ≤ +
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If you need a "system" of inequalities, then you need another equation.
There are infinite possibilities. Graph the points to see what works.
y < 8 or x > -2 are two examples.
---> I just realized that the system can be simpler than what I did above: