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solmaris [256]
3 years ago
5

If g(×)=ײ-× find g(1÷2)​

Mathematics
1 answer:
andrew11 [14]3 years ago
4 0
G x 0.5
answer = 0.5g
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Find the area of a circle with a Radius = 4 ft. Use 3.14 for and round to 2 decimal places.
bagirrra123 [75]

Answer:

50.24 ft^2

Step-by-step explanation:

Well formula for area of a circle is pi(radius)^2

so the radius is 4 so you square that it’ll be 16

then do 16(3.14)

you’ll get 50.24

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Step-by-step explanation:

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The table shows the weight gain of a kitten over a
stepan [7]

Answer:

The rate of change of the weight of kitten A is greater than the rate of change of the weight of kitten B

Step-by-step explanation:

  • The rate of change of the linear relationship is the slope of the line which represent this relationship
  • The rule of the slope is m = \frac{y2-y1}{x2-x1} , where (x1, y1) and (x2, y2) are 2 points on the line

∵ The table shows the weight gain of kitten A

→ Choose two points from the table to find the slope

∵ Points (0, 3) and (1, 7) are two points in the table

∴ x1 = 0 and y1 = 3

∴ x2 = 1 and y2 = 7

→ Substitute them in the rule of the slope above

∵ m = \frac{7-3}{1-0} = \frac{4}{1} = 4

∵ The slope is the rate of change

∴ The rate of change of the weight of kitten A is 4 oz/week

∵ The graph shows the weight gain of kitten B

→ Choose two points on the line to find the slope

∵ Points (0, 4) and (2, 10) lies on the line

∴ x1 = 0 and y1 = 4

∴ x2 = 2 and y2 = 10

→ Substitute them in the rule of the slope above

∵ m = \frac{10-4}{2-0} = \frac{6}{2} = 3

∵ The slope is the rate of change

∴ The rate of change of the weight of kitten B is 3 oz/week

→ By comparing the two rates

∵ The rate of change of kitten A is 4 oz per week

∵ The rate of change of kitten B is 3 oz per week

∴ The rate of change of the weight of kitten A is greater than

   the rate of change of the weight of kitten B

7 0
3 years ago
Which graph represents the function of f(x) = 9x^2 – 36/3x+6?
lubasha [3.4K]

Answer:

This graph represents the function above.

4 0
3 years ago
A circular field has a diameter of 50 yards. If a fence needs to be built to go around the field, how many yards of fencing are
Xelga [282]

Answer:

A.

Step-by-step explanation:

A fence is needed for the circular field.

Circumference is basically perimeter but for circles.

Knowing this information, we can use the formula for circumference.

C = \pid

C = (3.14)(50)

C = 157

hope it helps :)

4 0
3 years ago
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