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Anika [276]
3 years ago
5

Find the area of a circle with a Radius = 4 ft. Use 3.14 for and round to 2 decimal places.

Mathematics
2 answers:
Svetach [21]3 years ago
8 0
A= Pi * r2^
A= 3.14 * 4^2
A= 3.14 * 16
A= 50.26
bagirrra123 [75]3 years ago
6 0

Answer:

50.24 ft^2

Step-by-step explanation:

Well formula for area of a circle is pi(radius)^2

so the radius is 4 so you square that it’ll be 16

then do 16(3.14)

you’ll get 50.24

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If (72)p = 76, what is the value of p?<br><br> 2<br> 3<br> 4<br> 8
o-na [289]

Answer:

it would be +2

Step-by-step explanation:

the equation would be (72)+2= 76

3 0
4 years ago
What is an equivalent expression for 3 3-5?<br> ?
liubo4ka [24]

Answer: 18/5

Step-by-step explanation:5x3=15/5 + 3/5=18/5

4 0
3 years ago
A circle with a circumference of 51 inches to find the area
Kaylis [27]

\textit{circumference of a circle}\\\\ C=2\pi r~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ C=51 \end{cases}\implies 51=2\pi r\implies \boxed{\cfrac{51}{2\pi }=r} \\\\[-0.35em] ~\dotfill\\\\ \textit{area of a circle}\\\\ A=\pi r^2\qquad \implies A=\pi \left( \cfrac{51}{2\pi } \right)^2\implies A=\cfrac{51^2}{2^2\pi }\implies A\approx 206.98

4 0
3 years ago
The polygons below are similar, but not drawn to scale. find the value of x
gulaghasi [49]

Answer:

x=21

Step-by-step explanation:

Set the two similar sides in a fraction to be compared and set them equal to another set of similar sides whose values are already known. Solve from there. See work for more.

8 0
3 years ago
~~~30 POINTS~~~<br> Please answer this math question!
Nina [5.8K]
With a dilation, each dimension increases by the factor.  Thus, if we let the dimensions be x and y, the new dimensions are 2x and 2y.

(a): The original perimeter is 2(x+y), but the new one is 2(2x+2y).  This is twice the original perimeter, so it is 18*2=36.

(b): The original area is xy, and the new one is (2x)(2y), or 4xy.  This is four times the original area, or 20*4=80.

(c): As it's given that the side lengths are integers, the intended solution is most likely to divide by 2 in the perimeter to see that the sum of the side-lengths is 9 and their product is 20.  Guessing/checking values for each side, we see that 4 and 5 work for the smaller rectangle.  Multiplying by two, the larger one has lengths 8 and 10.

Alternatively, we set them to x and y and use the equations:
x+y=9
xy=20

Dividing by y, we see that x=20/y.  Substituting, we have that y+20/y=9.  Subtracting 9 and multiplying by y, we have:

y^2-9y=20

Factoring, we have (y-5)(y-4)=0.  The solutions to this equation are 4 and 5, which result in x=5, y=4 or x=4, y=5 respectively.  Thus, we see that 4 and 5 are the side-lengths.  Note that this solution did not require the assumption that the side-lengths are integers!
7 0
4 years ago
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