Answer:
The fraction of the tank is filled with gasoline is
.
Step-by-step explanation:
Consider the provided information.
Jamal filled his gas tank and then use 7/16 of the tank for traveling to visit his grandfather.
After his first traveling the amount of gas left can be calculated as:



He then used 1/3 of the remaining gas in the tank to run around town.
That means he left with 2/3 of gas.


Hence, the fraction of the tank is filled with gasoline is
.
This would be y=-4x-8. This equation is in slope-intercept form, where the slope is -4/1 and the y-intercept is at point (0,-8).
For a <span>system of two linear equations to have more than one
solution, the lines representing the equations must coincide, i.e. must
be the same or a multiple of each other. In that case, the system will have infinitely many solutions.
</span>
Answer:
70%
Step-by-step explanation:
Therefore, we can conclude that the required percentage is 70% that is 70% of 80 is 56.
<em>Hopes This Helps :)</em>
Answer:
Seee answer below.
Step-by-step explanation:
a. k = −1
If K=-1 the equation gets this form:
(x^2/-1) -y^2=1
There aren't natural numbers that being negative, adding them, we get 1 as result. So there is no graph for this equation.
b. k = 1
(x^2/1) -y^2=1
This is the natural form of the equation of an hyperbola. Attached you can find the graph.
c. k = 2
(x^2/2) -y^2=1
This is the natural form of the equation of an hyperbola. Attached you can find the graph.
d. k = 4
(x^2/4) -y^2=1
This is the natural form of the equation of an hyperbola. Attached you can find the graph.
e. k = 10
(x^2/10) -y^2=1
This is the natural form of the equation of an hyperbola. Attached you can find the graph.
f. k = 25
(x^2/25) -y^2=1
This is the natural form of the equation of an hyperbola. Attached you can find the graph.
g. Describe what happens to the graph of
x2 / k − y2 = 1 as k → [infinity].
As K is increasing the value of X will be tending to 0. So the equation for this will be:
− y^2 = 1.The solution for this is in the domain of the imaginary numbers.