What is the base, x, of the isosceles trapezoid rounded to the nearest hundredth of a centimeter?
2 answers:
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Answer:
A. (2x-3)/2
Step-by-step explanation:
Performing the long division indicated by the perimeter expression, you find ...
perimeter = (2x -3) + (10x +6)/(x^2 +2x)
Comparing this to the formula for the perimeter ...
perimeter = 2W +2L
where L is said to be of the form (ax +b)/(x^2 +2x)
we can match terms in the perimeter expression to see that ...
2W = 2x -3
2L = (10x +6)/(x^2 +2x)
The problem doesn't ask for it, but we can see that (a, b) = (5, 3). We can also see that ...
W = (2x -3)/2 . . . . . . . matches choice A
