All categories

3 years ago

SALE

Mathematics

1 answer:

kati45 [8]3 years ago

8 0

Answer:

$132

Step-by-step explanation:

$440-440×0.70

=$132

You might be interested in

Imagine that these are test scores on a Statistics examinations (test):

yanalaym [24]

Answer:

Step-by-step explanation:

7 0

2 years ago

US THE DISTRIBUTIVE PROPERTY TO ANSWER

Svetradugi [14.3K]

Answer:

1. -6t - 18

2. 21n - 14

3. -28 + 7t

4. 5m - 30

5. -48 + 8c

6. -15y -24

Step-by-step explanation:

Hope this helps!!!

3 0

3 years ago

You have invested in three different stocks: Engineering Aces, Upton Clothiers, and Thompson Musical Instruments. Because you ha

Serga [27]

Answer:

answer is 0.001254.

Step-by-step explanation:

Given that you invested in 3 stocks of Engineering Aces, Upton Clothiers, and Thompson Musical Instruments.

Also given that each stock value is independent of the other.

Let E be the event changing in value by more than 10% in a given week for Engineering Aces,

U be the event changing in value by more than 10% in a given week for Upton Clothiers, and T be the event changing in value by more than 10% in a given week for Thompson Musical Instruments.

Given that P(E) = = 19%

P(U) = 11%

P(T) = 6%

probability that all three will change by more than 10% in the same week

= P(EUT)

= P(E) P(U) P(T) since three events are independent.

=0.19(0.11)0.06

= 0.001254

8 0

3 years ago

I need the answer for this problem please

Savatey [412]

Answer:

Step-by-step explanation:

Find all probabilities:

A. False

$Pr(\text{red shirt}|\text{large shirt})=\dfrac{\text{number red large shirts}}{\text{number large shirts}}=\dfrac{42}{77}=\dfrac{6}{11}\\ \\Pr(\text{large shirt})=\dfrac{\text{number large shirts}}{\text{number shirts}}=\dfrac{77}{165}=\dfrac{7}{15}$

B. True

$Pr(\text{blue shirt}|\text{large shirt})=\dfrac{\text{number blue large shirts}}{\text{number large shirts}}=\dfrac{35}{77}=\dfrac{5}{11}\\ \\Pr(\text{blue shirt})=\dfrac{\text{number blue shirts}}{\text{number shirts}}=\dfrac{75}{165}=\dfrac{5}{11}$

C. False

$Pr(\text{shirt is medium and blue})=\dfrac{\text{number medium and blue shirts}}{\text{number shirts}}=\dfrac{48}{165}=\dfrac{16}{55}\\ \\Pr(\text{medium shirt})=\dfrac{\text{number medium shirts}}{\text{number shirts}}=\dfrac{88}{165}=\dfrac{8}{15}$

D. False

$Pr(\text{large shirt}|\text{red shirt})=\dfrac{\text{number red large shirts}}{\text{number red shirts}}=\dfrac{42}{90}=\dfrac{7}{15}\\ \\Pr(\text{red shirt})=\dfrac{\text{number red shirts}}{\text{number shirts}}=\dfrac{90}{165}=\dfrac{6}{11}$

4 0

3 years ago

Given the two graphs below, identify in two complete sentences one similarity and one difference between the graphs.

Advocard [28]

Answer:

well one similarity is that they both cross over zero and one difference is that one is going verticl and one is going up and down

Step-by-step explanation:

7 0

2 years ago