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3 years ago

The product of -2 and a number minus six is greater than -18

1 answer:

7 0

So, its a multiplying question - the product. Also there are multiple answers from x = negative anything to positive 14, so i chose a number.

The product of -2 and a number minus six is greater than -18.

-2 · (x - 6) > -18

-2 · (7 - 6) > -18

-2 · (1) > -18

-2 > -18

x = 7, or anything lower than 15.

On the number line btw, -2 is bigger than -18

You might be interested in

Solve the following inequality 5x+12+3x<36

Anni [7]

Answer:

x<3

Step-by-step explanation:

5x+12+3x<36

First subtract 12 from both sides.

5x+3x<24

Next combine like terms on the left side (5x and 3x)

8x<24

Next divide 8 from both sides

x<3

5 0

3 years ago

What are the solutions to the equation x² + 16x + 14 = 0?

poizon [28]

Answer:

-8+5√2 and -8-5√2

Step-by-step explanation:

Given the expression x² + 16x + 14 = 0

USing the general formulas

x = -16±√16²-4(14)/2

x = -16±√256-56/2

x = -16±√200/2

x = -16±10√2/2

x = -8±5√2

Hence the required solutions are -8+5√2 and -8-5√2

3 0

3 years ago

If 5 + 20 times 2 Superscript 2 minus 3 x Baseline = 10 times 2 Superscript negative 2 x Baseline + 5, what is the value of x? –

sp2606 [1]

Answer:

<h3>Option D) 3 is correct</h3><h3>Therefore the value of x is 3</h3>

Step-by-step explanation:

Given equation is $5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

<h3>To find the value of x :</h3>

First solving the given equation we have,

$5+20\times (2)^{2-3x}=10\times (2)^{-2x}+5$

$5+20\times (2)^{2-3x}-5=10\times (2)^{-2x}+5-5$

$20\times (2)^{2-3x}=10\times (2)^{-2x}$

$20\times (2)^2.(2)^{-3x}=10\times (2)^{-2x}$

$20\times 4.(2)^{-3x}=10\times (2)^{-2x}$

$80(2)^{-3x}=10\times (2)^{-2x}$

$\frac{80}{10}(2)^{-3x}=\frac{10\times (2)^{-2x}}{10}$

$8(2)^{-3x}=(2)^{-2x}$

$\frac{(2)^{-3x}}{(2)^{-2x}}=\frac{1}{8}$

$(2)^{-3x}.(2)^{2x}=\frac{1}{2^3}$ ( by using the property $\frac{1}{a^{-m}}=a^m$ )

$2^{-3x+2x}=\frac{1}{2^3}$ ( by using the property $a^m.a^n=a^{m+n}$ )

$2^{-x}=\frac{1}{2^3}$

$\frac{1}{2^x}=\frac{1}{2^3}$ ( by using the property $a^{-m}=\frac{1}{a^m}$ )

Since bases are same so powers are same

Therefore we can equate the powers we get x=3

<h3>Therefore the value of x is 3</h3><h3>Option D) 3 is correct</h3>

5 0

3 years ago

Read 2 more answers

Please help with these 3 questions and show all work!

Bas_tet [7]

Question 1:
"Match" the letters
DE are the last two letters of BCDE
The last two letters of OPQR is QR
DE is congruent to QR

Question 2:
Blank 3: Reflexive property (shared side)
Blank 4: SSS congruence of triangles (We have 3 sets of congruent sides)

Question 3:
I'm guessing those two numbers are 7.
Since both are 7, AB and AE are congruent.
We know that all the other sides are congruent because it is given.
We also know that there is a congruent angle in each triangle.
Thus, the two triangles are congruent by SAS or SSS.
(Note: I couldn't prove this without the two "7"s because there is no such thing as SSA congruence)

Have an awesome day! :)

8 0

3 years ago

2c divided by 3b, for b=2 and c=6

Levart [38]

(2c) / (3b)

(2*6) / (3*2) =
12/6 =
2 <===

8 0

3 years ago

Read 2 more answers