Tan²( θ ) - (1 + √3) tan (θ) + √3 = 0
tan²( θ ) - (tan (θ) + √3 tan (θ)) + √3 = 0
tan²( θ ) - tan (θ) - √3 tan (θ) + √3 = 0
tan( θ ) ( tan (θ) - 1) - √3 ( tan (θ) - 1 ) = 0
( tan( θ ) - 1 ) ( tan( θ ) - √3 ) = 0
tan( θ ) - 1 = 0
θ = π/₄
tan( θ ) - √3 = 0
θ = π/₃
so θ = π/₄ and θ = π/₃
Answer:
6s-35
Step-by-step explanation:
not sure
Answer:
C.
Step-by-step explanation:
The random variable W is Normal, with a mean of 28 ounces and a standard deviation of four ounces.
mean of total = 7+7+7+7 = 28
Variance of total = 4+4+4+4 = 16
SD of total = sqrt(16) = 4
