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In-s [12.5K]
3 years ago
10

Module 5 (part 1) Assignment - Quadratic Equations

Mathematics
2 answers:
Virty [35]3 years ago
4 0
A,e,f have 2 solutions
Kryger [21]3 years ago
4 0
A,E, and F. I hope it helps you
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14n=56
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Pizza Paradise offers 4 types of crust, 10 toppings, and 8 kinds of cheese for the mega calzone. How many different mega calzone
Bumek [7]

Answer:

26880 ways

<em></em>

Step-by-step explanation:

Given

Crust = 4

Toppings = 10

Cheese = 8

Required

Determine the number of ways 3 toppings and 3 cheese can be selected

The number of crusts to be selected was not stated. So, I'll assume 1 crust to be selected from 4.

This can be done in ^4C_1 ways

For the toppings:

3 can be selected from 10 in ^{10}C_3 ways

For the cheeses:

3 can be selected from 8 in ^{8}C_3 ways

Total number of selection is:

Total = ^4C_1 * ^{10}C_3 * ^{8}C_3

Apply combination formula:

Total = \frac{4!}{(4-1)!1!} * \frac{10!}{(10-3)!3!} * \frac{8!}{(8-3)!3!}

Total = \frac{4!}{3!1!} * \frac{10!}{7!3!} * \frac{8!}{5!3!}

Total = \frac{4*3!}{3!*1} * \frac{10*9*8*7!}{7!*3*2*1} * \frac{8*7*6*5!}{5!*3*2*1}

Total = \frac{4}{1} * \frac{10*9*8}{3*2*1} * \frac{8*7*6}{3*2*1}

Total = 4 * \frac{720}{6} * \frac{336}{6}

Total = 4 * 120* 56

Total = 26880

<em>Hence, there are 26880 ways</em>

5 0
3 years ago
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