Let us try and solve it analytically. We have that the side=x+3 together with the short side=s and the diagonal=x+4 satisfy the Pythagorean Theorem. Then we have that
. This yields
which yields s^2=2x+7, hence a) is the correct answer.
A = l x w
so you know that the length is 3m longer than the width, so you could use a formula to represent that
w = l + 3
you then substitute the second equation into the first to solve for l
70 = l x (l +3)
70 = l^2 + 3l
you could then rearrange the formula and solve for l using the quadratic formula
0 = l^2 + 3l - 70
l = -3 +- (square root (3)^2 - 4(1)(70)) / 2(1)
l = -3 +- (square root 9 + 280) / 2
l = -3 +- (square root 289) / 2
l = -3 +- 17 / 2
then you solve for the two seperate roots
l = -3 + 17 /2
l = 14 / 2
l = 7
or
l = -3 - 17 / 2
l = -20 / 2
l = -10
since a length cannot be negative, this root is not viable. therefore l = 7
to solve for w you would use
w = l + 3
w = 7 + 3
w = 10
hope this helps! if you did not understand a step or concept please let me know!
First step: partition the number you want to square root into a block of 2 digits, starting from the last digit (first diagram)
Second step: As our number is a five-digits, we ends up with 2 28 01. Pick a number that could be squared to get the first partition, 2. This number is 1, since 1×1=1
Third step: Write 1 on the top and on the side, as shown in the second graph
Fourth step: Double the number on the side, which is 1+1=2 and use this number as the first digit for the next multiplier. Meanwhile, subtract 1 from 2 inside the root sign to get 1, then pull the other two digits, 28
Fifth step: We need a value in the boxes that when we multiply together will give a number less than 128. We choose 5 as 25×5=125
Sixth step: Subtract 125 from 128 to give 3, and as the same concept with long division, bring down the 0 and the 1. So we have 301
Seventh step: Add 5 to the multiplier on the left, so 20+5=30, which we will use on the side as the hundred and ten digits.
Final step: Find a number to fit in the boxes. We choose 1 since 301×1=301
And hence the square root of 228801 is 151
Answer: C
<u>Step-by-step explanation:</u>
∑ 8(
)⁽ⁿ⁻¹⁾ from n = 1 to n = 5
n = 1 → 8()⁽¹⁻¹⁾
= 8 = 
n = 2 → 8()⁽²⁻¹⁾
= 
= 
n = 3 → 8()⁽³⁻¹⁾
= 
= 
n = 4 → 8()⁽⁴⁻¹⁾
= 
= 
n = 5 → 8()⁽⁵⁻¹⁾
= 
=
Sum = 
= 408.99
Answer:
The answer is y = 4
x − 4
Step-by-step explanation:
