Yes I love this problem so good
Answer:
A stone is thrown straight up from the edge of a roof, 750 feet above the ground at a speed of 14 feet per second. A) Remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 2 seconds later? B) At what time does the stone hit the ground? C) What is the velocity of the stone when it hits the ground?
Step-by-step explanation:
A stone is thrown straight up from the edge of a roof, 750 feet above the ground at a speed of 14 feet per second. A) Remembering that the acceleration due to gravity is -32 feet per second squared, how high is the stone 2 seconds later? B) At what time does the stone hit the ground? C) What is the velocity of the stone when it hits the ground?
Answer:

Step-by-step explanation:
8x + 34 = 130 <u>(Vertical Angles are Equal)</u>
Subtract 34 to both sides
8x = 130 - 34
8x = 96
Divide both sides by 8
x = 96 / 8
x = 12
![\rule[225]{225}{2}](https://tex.z-dn.net/?f=%5Crule%5B225%5D%7B225%7D%7B2%7D)
Hope this helped!
<h3>~AH1807</h3>
Answer:
314 * 2
Step-by-step explanation: