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aliya0001 [1]
3 years ago
8

When b > 1, as x grows in the negative direction, y______ . When 0 < b < 1, as x grows in the negative direction, y____

_ .
Mathematics
1 answer:
sweet-ann [11.9K]3 years ago
3 0

Answer:

decrease, increase.

Step-by-step explanation:

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Recycling Center A processes aluminum at a rate of 100 pounds per hour, while Recycling Center B processes aluminum at a rate of
maria [59]
I believe it is Recycling center A
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3 years ago
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About 13​% of the population of a large country is nervous around strangersnervous around strangers. If two people are randomly​
Molodets [167]

Answer:

1.69% probability both are nervous around strangers.

24.31% probability at least one is nervous around strangers.

Step-by-step explanation:

For each person, there are only two possible outcomes. Either they are nervous around strangers, or they are not. The people are chosen randomly, which means that the probability of a person being nervous around strangers is independent from other people. So we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

About 13​% of the population of a large country is nervous around strangers.

This means that p = 0.13.

Two people are randomly​ selected

This means that n = 2.

What is the probability both are nervous around strangers?

This is P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{2,2}.(0.13)^{2}.(0.87)^{0} = 0.0169

1.69% probability both are nervous around strangers.

What is the probability at least one is nervous around strangersnervous around strangers?

This is P(X \geq 1)

P(X \geq 1) = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{2,1}.(0.13)^{1}.(0.87)^{1} = 0.2262

P(X = 2) = C_{2,2}.(0.13)^{2}.(0.87)^{0} = 0.0169

P(X \geq 1) = P(X = 1) + P(X = 2) = 0.2262 + 0.0169 = 0.2431

24.31% probability at least one is nervous around strangers.

3 0
3 years ago
Solve for x.<br> (17x - 23)<br> (&amp;r - 4)*<br> -(3x + 17)
Finger [1]

Answer:

17rx2−23rx−71x+75

Step-by-step explanation:

(17x−23)(xr−4)−(3x+17)

=(17x−23)(xr−4)+−1(3x+17)

=(17x−23)(xr−4)+−1(3x)+(−1)(17)

=(17x−23)(xr−4)+−3x+−17

=(17x)(xr)+(17x)(−4)+(−23)(xr)+(−23)(−4)+−3x+−17

=17rx2+−68x+−23rx+92+−3x+−17

=17rx2+−68x+−23rx+92+−3x+−17

=(17rx2)+(−23rx)+(−68x+−3x)+(92+−17)

=17rx2+−23rx+−71x+75

6 0
3 years ago
Please help me with these problems
Feliz [49]

Answer:

564

Step-by-step explanation:

4 0
3 years ago
The butcher sold 63.8 pounds of meat on Monday. He sold 25.3 pounds more than that on Tuesday. On Wednesday, he sold 14.5 pounds
Elena-2011 [213]
Monday: 63.8
Tuesday: 63.8 + 25.3 = 89.1
Wednesday: 89.1 + 14.5 = 103.6

63.8 + 89.1 + 103.6 = 256.5

The butcher sold 256.5 pounds of meat over the three days.
7 0
3 years ago
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