Answer:
13.567%
Step-by-step explanation:
We solve the above question, using z score formula
z = (x-μ)/σ, where
x is the raw score = 23.1 ounces
μ is the population mean = 22.0 ounces
σ is the population standard deviation = 1.0 ounce
More than = Greater than with the sign = >
Hence, for x > 23.1 ounces
z = 23.1 - 22.0/1.0
= 1.1
Probability value from Z-Table:
P(x<23.1) = 0.86433
P(x>23.1) = 1 - P(x<23.1)
P(x>23.1) = 1 - 0.86433
P(x>23.1) = 0.13567
Converting to percentage
= 0.13567 × 100
= 13.567%
Therefore, the percentage of regulation basketballs that weigh more than 23.1 ounces is 13.567%
Answer:
x = 45/8
Step-by-step explanation:
8x – 3y = 36
Let y=3
8x – 3*3 = 36
8x - 9 = 36
Add 9 to each side
8x -9+9 = 36+9
8x = 45
Divide each side by 8
8x/8 = 45/8
x = 45/8
Answer:
A line segment is <u><em>always</em></u> similar to another line segment, because we can <u><em>always</em></u> map one into the other using only dilation a and rigid transformations
Step-by-step explanation:
we know that
A<u><em> dilation</em></u> is a Non-Rigid Transformations that change the structure of our original object. For example, it can make our object bigger or smaller using scaling.
The dilation produce similar figures
In this case, it would be lengthening or shortening a line. We can dilate any line to get it to any desired length we want.
A <u><em>rigid transformation</em></u>, is a transformation that preserves distance and angles, it does not change the size or shape of the figure. Reflections, translations, rotations, and combinations of these three transformations are rigid transformations.
so
If we have two line segments XY and WZ, then it is possible to use dilation and rigid transformations to map line segment XY to line segment WZ.
The first segment XY would map to the second segment WZ
therefore
A line segment is <u><em>always</em></u> similar to another line segment, because we can <u><em>always</em></u> map one into the other using only dilation a and rigid transformations
Answer:
Step-by-step explanation:
Given the explicit function as
f(n) = 15n+4
The first term of the sequence is at when n= 1
f(1) = 15(1)+4
f(1) = 19
a = 19
Common difference d = f(2)-f(1)
f(2) = 15(2)+4
f(2) = 34
d = 34-19
d = 15
Sum of nth term of an AP = n/2{2a+(n-1)d}
S20 = 20/2{2(19)+(20-1)15)
S20 = 10(38+19(15))
S20 = 10(38+285)
S20 = 10(323)
S20 = 3230.
Sum of the 20th term is 3230
For the explicit function
f(n) = 4n+15
f(1) = 4(1)+15
f(1) = 19
a = 19
Common difference d = f(2)-f(1)
f(2) = 4(2)+15
f(2) = 23
d = 23-19
d = 4
Sum of nth term of an AP = n/2{2a+(n-1)d}
S20 = 20/2{2(19)+(20-1)4)
S20 = 10(38+19(4))
S20 = 10(38+76)
S20 = 10(114)
S20 = 1140
Sum of the 20th terms is 1140
