The least number of quadratic system can have is Two real solutions or no real solutions.
Answer:
640.0
Step-by-step explanation:
Answer:
y=6x+8 or y=6x-22
Step-by-step explanation:
use the equation y=mx+b
m is the slope and b is the y-intercept
to find the slope use the equation m = y2-y1 over x2-x1
-22 - 8 / -2 - 3 = -30 / -5 = 6
6 is your slope and for the y-intercept you can choose whichever y-intercept to put into the equation.
HOPE THIS HELPS!!
Answer:
12
Step-by-step explanation:
15 - 3 = 12
