Given:
In ΔNOP, the measure of ∠P=90°, PN = 95 feet, and OP = 31 feet.
To find:
The measure of ∠O to the nearest degree.
Solution:
In a right angle triangle,
In triangle NOP,
Therefore, the measure of angle O is 72 degrees.
Answer:
SA = 2*L*W+2*H+2*W*H
Step-by-step explanation:
The length is the side going from left to right, the width is the side going from front to back, and the height is the side going from top to bottom.
Answer:
Step-by-step explanation:
Question 1 is 2.
Question 2. 3 3/5 + 3 3/5 = 6 6/5 which equals 7 1/5 if you add another one.
so the answer for question 2 is " 1.521.
That would be 140
10% is basically the same thing as 1/10. So if you want to find the answer, do the opposite of 1/10, which is 10.
That way, you can get 14 * 10 = 140
To solve this, you’ll first need to solve for their slopes.
The slope for line Q is y2-y1/x2-x1 = -8-(-2)/-8-(-10) = -3
We know that the lines are perpendicular so the negative reciprocal of -3 is 1/3
The equation you get it y = 1/3x + b.
Now you will need to solve for b by substituting in the first ordered pair of line R.
2 = 1/3(1) + b.
Once you solve for b, you should get 5/3 and y = 1/3x + 5/3
Now, to find a, you will need to substitute in 10 from the second ordered pair into x in your new equation.
y = 1/3(10) + 5/3.
Your solution should be 5.
So your answer is: a = 5
