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Airida [17]
3 years ago
12

Pleaseee helpppp!!!!

Mathematics
1 answer:
taurus [48]3 years ago
5 0

Answer:

Substitute the given value into the function and evaluate.

2 x 3 + 7 x 2 − 4 x − 15

Step-by-Step Process

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The triangle is a right triangle and on the left is 5 on the bottom is 12.
spayn [35]

Answer:

B. 13

Step-by-step explanation:

To find the missing hypotenuse of a right triangle we can use this formula:

c = \sqrt{(a^{2} } +b^{2} )

Lets solve:

c = \sqrt{5^{2} + 12^{2} }

c = \sqrt{25 + 144}

c = \sqrt{169}

c = 13

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3 years ago
Expand logarithm log(7•11)
alexandr1967 [171]
Log7+log11=log(7•11)
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Fill in the blanks with <,>,= symbols( -3)+(-19)+6...................(-41)-15+9​
earnstyle [38]
<h3>First we will simplify both equations....</h3><h2>#1</h2>

( - 3) + ( - 19) + 6 \\  - 3 + ( - 19) + 6 \\  - 3 - 19 + 6 \\  =  - 16

<h2>#2</h2>

( - 41) - 15 + 9 \\  - 41 - 15 + 9 \\  =  - 47

<h2>Now,</h2>

- 16 >  - 47

<h2>How?</h2>

  • When the number is in negative the smaller number is greater than the greater number.
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You have at most 8 hours to spend at a concert and at park. You want to spend at least 3 hours at the concert and more than 4 ho
Wewaii [24]
Bottom right is correct
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Circle the correct words in each of the following statements.Given that x(t) is a real function with the Fourier transform X(f):
Kryger [21]

Answer:

(a) even function

(b) odd function

Step-by-step explanation:

From the given information;

Any function x(t) can be said to be the sum of even and odd functions.

i.e.

x(t) = x_e(t) + x_o(t)

where;

x(t) is a real function.

For a  real and even function, the Fourier transform is also real and even.

x_e(t)  \iff x_e(f) \\ \\

Also, the Fourier Transform of a real and odd function is imaginary and odd.

x_o(t) \iff x_o(f)

The behavior of X(f) largely depends on the behavior of x(t).

If x(t) is real and even, then x(f) is real and even valued function

Thus, the real part of X(f) is an even function.

If x(t) is real and odd, then x(f) is imaginary and odd valued function

Thus, the imaginary part of X(f) is an odd function.

8 0
3 years ago
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