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qwelly [4]
3 years ago
9

A. 35 B. 85 C. 50 D. 25

Mathematics
1 answer:
vivado [14]3 years ago
4 0

Answer: B

Step-by-step explanation:

Use the exterior angle theorem, which states that the exterior angle of a triangle is equal to the sum of the two remote interior angles.

In this case: 120-x= 10+x+60

Simplifying it by combining like terms: 120-x=70+x

Solving by isolating the variable: 50= 2x, x=25

Now use what we know, which is that angle A is 35 degrees, and angle B is 60, to find out that the correct answer is B, 85 degrees.

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What is the measure of angle A?
I am Lyosha [343]

First you have to find the angle B (check attachment)

B = 180^{\circ} - 137^{\circ} = 43^{\circ}\\

Then you can find the last angle inside the triangle, which I'll call C

C = 180^{\circ} - 102^{\circ} - 43^{\circ} = 35^{\circ}

Now you can find angle A

A = 180^{\circ} - C = 180^{\circ} - 35^{\circ} = 145^{\circ}

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4 years ago
Please show work and solve :)
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Answer:

c = 24

Step-by-step explanation:

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Read 2 more answers
An educator claims that the average salary of substitute teachers in school districts is less than $60 per day. A random sample
valentina_108 [34]

Answer:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

Step-by-step explanation:

Information given

60, 56, 60, 55, 70, 55, 60, and 55.

We can calculate the mean and deviation with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Replacing we got:

\bar X=58.875 represent the mean

s=5.083 represent the sample standard deviation for the sample  

n=8 sample size  

\mu_o =60 represent the value that we want to test

\alpha=0.1 represent the significance level

t would represent the statistic

p_v represent the p value

Hypothesis to test

We want to test if the true mean is less than 60, the system of hypothesis would be:  

Null hypothesis:\mu \geq 60  

Alternative hypothesis:\mu < 60  

The statistic would be given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing the info we got:

t=\frac{58.875-60}{\frac{5.083}{\sqrt{8}}}=-0.626    

The degrees of freedom are given by:

df=n-1=8-1=7  

The p value would be given by:

p_v =P(t_{(7)}  

Since the p value is higher than 0.1 we have enough evidence to FAIl to reject the null hypothesis and we can't conclude that the true mean is less than 60

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