9(x + 1)^4 - 19(x + 1)^2 + 2 = 0
After expanding and re-factoring, we have:
(3x + 2)(3x + 4)(x^2 + 2x - 1) = 0
solutions are x = -2/3, x = -4/3, x = -1 - sqrt(2), x = sqrt(2) - 1
Answer:
Ignoring unwritten factors of 1, what is the sum of the numerical factors in the expression below?
−4(x−2)+(x−2)7−(x+5)(x−2)+(x−2)9+(−3)(x−2)
(1 point)
Step-by-step explanation:
The sum is 5
Answer:
z = 8
Step-by-step explanation:
PythagoreanTheorem
a^2 + b^2 = c^2
a and b stand for the legs while c stands for the hypotenuse. Since we have the numeral for one of the legs and the hypothenuse, we can plug those into the formula.
a^2 + 15^2 = 17^2
a^2 = 64
a = 8
Answer:
the third function
Step-by-step explanation:
when looking at x=-1 the value goes from (x=-2) 0 to -3, when x=0 it goes to 0, and then only increases after that.
It is a reciprocal. Multiplying is the opposite of Dividing, so if I multiply 3 times 4 I get 12. If i divide 12 by 3 I get 4.
