So you you are trying to find the area of sphere so you would use this formula
A=4•3.14•r^2
And you already know that the radius is 6 so you would go ahead and plug in the numbers
A=4•3.14•4^2
4^2 is 16 so your final equation would be
A=4•3.14•16
And your answer is
=452.39
Answer:
Parallel
<u>Step-By-Step Explanation:</u>
Put the Function in Slope Intercept Form and Find the Slope of 6x+3y = 15
6x+3y = 15
3y = -6x + 15
3y/3 = -6x/3 + 15/3
y = -2x + 5
<u>We can see that the slope of 6x+3y = 15 is -2</u>
Put the Function in Slope Intercept Form and Find the Slope of y–3=–2x
y–3=–2x
y = -2x + 3
Here are our two Functions In Slope Intercept Form
y = -2x + 5
y = -2x + 3
<u>Remember the m = slope and the b = y-intercept</u>
y = mx + b
y = -2x + 5
y = -2x + 3
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We can see both equations have the same slope of -2 so this means they could be parallel because parallel functions have the same slope but coinciding functions have the same slope too. To tell if the two functions are coinciding, the functions need to have the same slope and the same y-intercept. Looking at the two functions, we can see they have the same slope of -2 but their y-intercept are different so this makes the two functions parallel.
Answer:
-210
<em>good luck, i hope this helps :)</em>
<em />
Y = x + 5A linear equation (in slope-intercept form) for a line perpendicular to y = -x + 12 with a y-intercept of 5.y = 1/2x - 5Convert the equation 4x - 8y = 40 into slope-intercept form.y = -1/2x + 5A linear equation (in slope-intercept form) which is parallel to x + 2y = 12 and has a y-intercept of 5.3x - y = -5A linear equation (in standard form) which is parallel to the line containing (3, 5) and (7, 17) and has a y-intercept of 5.y = -3x + 1A linear equation (in slope-intercept form) which contains the points (10, 29) and (-2, -7).y = -5A linear equation which goes through (6, -5) and (-12, -5).x = -5A linear equation which is perpendicular to y = 12 and goes through (-5, 5).y = 5A linear equation which is parallel to y = 12 and goes through (-5, 5).y = -x + 5A linear equation (in slope-intercept form) which is perpendicular to y = x and goes through (3, 2).y = -5xA linear equation (in slope-intercept form) which goes through the origin and (1, -5).x = 2A linear equation which has undefined slope and goes through (2, 3).y = 3A linear equation which has a slope of 0 and goes through (2, 3).2x + y = -9A linear equation (in standard form) for a line with slope of -2 and goes through point (-1, -7).3x +2y = 1A linear equation (in standard form) for a line which is parallel to 3x + 2y = 10 and goes through (3, -4).y + 4 = 3/2 (x - 3)A linear equation (in point-slope form) for a line which is perpendicular to y = -2/3 x + 9 and goes through (3, -4).y - 8 = -0.2(x + 10)<span>The table represents a linear equation.
Which equation shows how (-10, 8) can be used to write the equation of this line in point-slope form?</span>
