All categories

2 years ago

What is the solution to the equation 8+4=2(x-1)? O 5 O11/2 O 13/2 O 7

Mathematics

2 answers:

maks197457 [2]2 years ago

8 0

Answer:

Step-by-step explanation:

Simplifying

8 + 4 = 2(x + 1)

Combine like terms: 8 + 4 = 12

12 = 2(x + 1)

Reorder the terms:

12 = 2(1 + x)

12 = (1 * 2 + x * 2)

12 = (2 + 2x)

Solving

12 = 2 + 2x

Solving for variable 'x'.

Move all terms containing x to the left, and all other terms to the right.

Add '-2x' to each side of the equation.

12 + -2x = 2 + 2x + -2x

Combine like terms: 2x + -2x = 0

12 + -2x = 2 + 0

12 + -2x = 2

Add '-12' to each side of the equation.

12 + -12 + -2x = 2 + -12

Combine like terms: 12 + -12 = 0

0 + -2x = 2 + -12

-2x = 2 + -12

Combine like terms: 2 + -12 = -10

-2x = -10

Divide each side by '-2'.

x = 5

Simplifying

x = 5

Nookie1986 [14]2 years ago

8 0

Answer:

x = 7

Step-by-step explanation:

Here are the steps I took to simplify this equation [to isolate x]:

8+4=2(x-1)

12 = 2x - 2

+ 2 + 2

14 = 2x

÷2 ÷2

7 = x

(check: 12 = 2 (7-1) -> 12 = 2(6) true statement means that answer is correct)

You might be interested in

3x²-30x+9=0<br> PLEASE HELP<br> COMPLETING THE SQUARE WILL MARK BRAINLIEST

nlexa [21]

Answer:

i have done the cutting of x's exponent

Step-by-step explanation:

= 3x - 30+9 =0

= 3x - 21 =0

= 3x= 21

= x = 21/3

x= 7 this the answer

7 0

3 years ago

Kyle’s account was overdrawn so that the account showed $9 less than zero. Kyle deposited $25 in the account. The next day he wi

SOVA2 [1]

X=(-9+25)-10 I think

7 0

4 years ago

Read 2 more answers

An urn contains 5 white and 10 black balls. A fair die is rolled and that number of balls is randomly chosen from the urn. What

galina1969 [7]

Answer:

Part A:

The probability that all of the balls selected are white:

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

$P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

Step-by-step explanation:

A is the event all balls are white.

D_i is the dice outcome.

Sine the die is fair:

$P(D_i)=\frac{1}{6}$ for i∈{1,2,3,4,5,6}

In case of 10 black and 5 white balls:

$P(A|D_1)=\frac{5_{C}_1}{15_{C}_1} =\frac{5}{15}=\frac{1}{3}$

$P(A|D_2)=\frac{5_{C}_2}{15_{C}_2} =\frac{10}{105}=\frac{2}{21}$

$P(A|D_3)=\frac{5_{C}_3}{15_{C}_3} =\frac{10}{455}=\frac{2}{91}$

$P(A|D_4)=\frac{5_{C}_4}{15_{C}_4} =\frac{5}{1365}=\frac{1}{273}$

$P(A|D_5)=\frac{5_{C}_5}{15_{C}_5} =\frac{1}{3003}=\frac{1}{3003}$

$P(A|D_6)=\frac{5_{C}_6}{15_{C}_6} =0$

Part A:

The probability that all of the balls selected are white:

$P(A)=\sum^6_{i=1} P(A|D_i)P(D_i)$

$P(A)=\frac{1}{6}(\frac{1}{3}+\frac{2}{21}+\frac{2}{91}+\frac{1}{273}+\frac{1}{3003}+0)\\ P(A)=\frac{5}{66}=0.075757576$

Part B:

The conditional probability that the die landed on 3 if all the balls selected are white:

We have to find $P(D_3|A)$

The data required is calculated above:

$P(D_3|A)=\frac{P(A|D_3)P(D_3)}{P(A)}\\ P(D_3|A)=\frac{\frac{2}{91}*\frac{1}{6}}{\frac{5}{66} } \\P(D_3|A)=\frac{22}{455}=0.0483516$

7 0

3 years ago

While researching facts

ioda

Multiply 23.93 by 14. There’s the answer

6 0

4 years ago

Evaluate 8x-6 when x=7

V125BC [204]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers