Solve x2 - 49 = 0 A) ±49 B) ±12 C) ±7 D) ±6

In triangle ABC, angle bisectors line AD, line BE, and line CF meet at I. If DI = 3, BD = 4, and BI = 5, then compute the area o

Nikitich [7]

The area of triangle ABC is the amount of space on the triangle

The area of the triangle is 54.84 square units

<h3>How to determine the area of triangle ABC</h3>

Start by drawing the triangle (see attachment)

Next, calculate the measure of angle B using the following tangent ratio

$\tan(B/2) = \frac 34$

This gives

$\tan(B/2) = 0.75$

Take the arc tan of both sides

$B/2 = 36.87$

Multiply by 2

$B = 73.74$

Next, calculate the length of side AD using the following equation

$AD = \tan(B) * BD$

This gives

$AD = \tan(73.74) * 4$

$AD =13.71$

The area of the triangle is then calculated as:

$Area = AD * BD$

This gives

$Area = 13.71 * 4$

$Area = 54.84$

Hence, the area of the triangle is 54.84 square units

Read more about areas at:

brainly.com/question/24487155

8 0

1 year ago

Of all of the individuals who develop a certain rash, suppose the mean recovery time for individuals who do not use any form of

VashaNatasha [74]

Answer:

z(s) is in the rejection region. We reject H₀. We dont have enought evidence to support that the cream has effect over the recovery time

Step-by-step explanation:

Sample information:

Size n = 100

mean x = 28,5

Population information

μ₀ = 30

Standard deviation σ = 8

Test Hypothesis

Null Hypothesis H₀ x = μ₀

Alternative Hypothesis Hₐ x < μ₀

We assume CI = 95 % then α = 5 % α = 0,05

As the alternative hypothesis suggest we should develop a one tail-test on the left ( we need to find out if the cream have any effect on the rash), effects on the rash could be measured as days of recovery

A z(c) for 0,05 from z-table is: z(c) = - 1,64

z(s) = ( x - μ₀ ) / σ/√n

z(s) = ( 28,5 - 30 ) / 8/√100

z(s) = - 1,5 * 10 / 8

z(s) = - 1,875

Comparing z(s) and z(c)

|z(s)| < |z(c)| 1,875 > 1,64

z(s) is in the rejection region. We reject H₀. We dont have enought evidence to support that the cream has effect over the recovery time

3 0

2 years ago

A circle is circumscribed around a square and another circle is inscribed in the square. If the area of the square is 9 in2, wha

lesantik [10]

Answer:

√2:1

Step-by-step explanation:

First we need to know that the length of the side of the square is equal to the diameter of the inscribed circle i.e

L = di

Given the area of the square to be 9in², we can get the length of the square.

Area of a square = L²

L is the length of the square.

9 = L²

L = √9

L = 3in

Hence the length of one side of the square is 3in

This means that the diameter of the inscribed circle di is also 3in.

Circumference of a circle = π×diameter of the circle(di)

Circumference of inscribed circle = π×3

= 3π in

For the circumscribed circumscribed circle, diameter of the outer circle will be equivalent to the diagonal of the square.

To get the diagonal d0, we will apply the Pythagoras theorem.

d0² = L²+L²

d0² = 3²+3²

d0² = 9+9

d0² = 18

d0 = √18

d0 = √9×√2

d0 = 3√2 in

Hence the diameter of the circumscribed circle (d0) is 3√2 in

Circumference of the circumscribed circle = πd0

= π(3√2)

= 3√2 π in

Hence, ratio of the circumference of the circumscribed circle to the one of the inscribed will be 3√2 π/3π = √2:1

8 0

2 years ago

Please help! asap multiple choice algebra 2

ddd [48]

Answer:

d

Step-by-step explanation:

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4 0

2 years ago

Solve 13/19-(-1/19) a.-12/19 b.-14/19 c.14/19 d.12/19

mojhsa [17]

Answer:

C

Any time you have a subtraction and a negitive right next to eachother, it means to add. So, you would add 13 and 1 to get 14, then keep the denominator 19 to get 14/19.

Step-by-step explanation:

7 0

1 year ago

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