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2 years ago

The digram repersents a 12cm by 4cm rectangule. Calcute the area of the rectangular,giving the units of your units

Mathematics

1 answer:

brilliants [131]2 years ago

6 0

Answer:

Step-by-step explanation:

area of rectangle = lxb

= 12 x 4

= 36 $cm^{2}$

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What value of q makes the equation true? 18/q=3/5 A.)6 B.)30 C.)25 D.)18

seropon [69]

B because 3 times 6 makes 18, so 5 times six is 30 which is B

6 0

2 years ago

How should I do this question

Ivanshal [37]

Answer:

( 11 -6)

( -5 6 )

Step-by-step explanation:

Multiply the first row of N by first column of M. This will give the first element in top row of the answer :-

-3*-2 + 1*5 = 11

Then multiply the first row in N by the second column of M to give the second element of the top row.

-3*0 + 1*-6 = -6

Then do a similar process with the second row in N.

8 0

3 years ago

Read 2 more answers

If you were given the data set $s $10, $10, $12, $13, $15, which measure of central

Katarina [22]

Answer: Mode

Step-by-step explanation:

The given data set is: 10, 10, 12, 13, 15

Mean is the average - find the sum of the data set and divide by the number of terms in the set: $\dfrac{10+10+12+13+15}{5} =\dfrac{60}{5}=12$

Mean = 12

Median is the middle term (when the data set is ordered from least to greatest).

Median = 12

Mode is the term that appears the most.

Mode = 10

Since you want to show that the prices are low, you would choose the lowest value. 10 is lower than 12, so the Mode is lower than either the Mean or the Median.

7 0

3 years ago

Write an algebraic rule to describe the translation C(5, –4)- ’(–2, 1).

Orlov [11]

A negative minus a negative is always a positive ;)

5 0

2 years ago

An object is launched at 29.4 meters per

Lerok [7]

Answer:

The reasonable domain for the scenario is option 'a';

a) [0, 7]

Step-by-step explanation:

For the projectile motion of the object, we are given;

The speed at which the object is launched, v = 29.4 meters per second

The height of the platform from which the object is launched, h = 34.3 meter

The equation for the height of the object as a function of time 'x' is given as follows;

f(x) = -4.9·x² + 29.4·x + 34.3

The domain for the scenario, is given by the possible values of 'x' for the function, which is found as follows;

At the height from which the object is launched, x = 0, and f(x) = 34.3

At the ground level to which the object can drop, f(x) = 0

∴ f(x) = -4.9·x² + 29.4·x + 34.3 = 0

-4.9·x² + 29.4·x + 34.3 = 0

By the quadratic formula, we have;

x = (-29.4 ± √(29.4² - 4 × (-4.9) × 34.3))/(2 × (-4.9)

∴ x = -1, or 7

Given that time is a natural number, we have the reasonable domain for the scenario as the start time when the object is launched, t = 0 to the time the object reaches the ground, t = 7

Therefore, the reasonable domain for the scenario is; 0 ≤ x ≤ 7 or [0, 7].

4 0

2 years ago