Answer:
I'm not sure if this is correct, but I would say it increased by maybe 29 percent so sorry if i'm wrong
Step-by-step explanation:
✔️0 < x < 1
X -3 < x < -2
✔️-1 < x < 0
X 2 < x < 3
Here's how you do it: you go to the graph, and go to the area where the function connects with 0, and follow it to the path where it connects with 1. Is that specific line decreasing or increasing? Nevermind what happens to it after/before those specific numbers, you're focusing on whether the function is increasing or decreasing from 0 to 1. The same apply to the other 3.
Answer:
There are some unknown characters in the answer list, so am not certain which letter. However, the expansion of (x^2 + y)^2 is:
x^4 + 2yx^2 + y^2.
Note: Am using the carrot - shift 6 - ^ to denote "to the power of".
Step-by-step explanation:
(x^2 + y)^2 = (x^2 + y) * (x^2 + y)
= (x^2 * x^2) + (y*x^2) + (y*x^2) + (y * y)
= x^4 + 2yx^2 + y^2
In words the answer is: x to the 4th plus 2 yx squared plus y squared.
Answer:
32
Step-by-step explanation:
Since there are 20 total pieces of gum, we divide 20 by 5 to figure out how many groups of 8 pieces of candy there are (For every 8, 5 are gum). This gives us 4 groups of 8. Because for every 8 pieces, 5 are gum, we subtract 5 from 8 and get three. Multiply 3 by 4 (the number of groups), and we get 12 other pieces of candy. Add to 20, and we get 32. To check, divide 32 by the number of groups (4) and we get 8, which is how many pieces of candy are in each group.
Answer:
(1) TRUE.
(2) FALSE.
(3) FALSE.
(4) TRUE.
(5) FALSE.
Step-by-step explanation:
(1) 

Thus, the equation is TRUE.
(2) 

Thus, the equation is FALSE.
(3) ![4^{\frac{1}{2} } = \sqrt[4]{64}](https://tex.z-dn.net/?f=4%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%20%3D%20%5Csqrt%5B4%5D%7B64%7D)
![4^{\frac{1}{2} }= \sqrt{4} = 2\\\\\sqrt[4]{64} = (64)^{\frac{1}{4} } = (2^6)^{\frac{1}{4} }= 2^{\frac{6}{4} } = 2^{\frac{3}{2} }=(\sqrt{2} )^3 = (\sqrt{2} \times \sqrt{2} \times \sqrt{2} ) = 2\sqrt{2}](https://tex.z-dn.net/?f=4%5E%7B%5Cfrac%7B1%7D%7B2%7D%20%7D%3D%20%5Csqrt%7B4%7D%20%3D%202%5C%5C%5C%5C%5Csqrt%5B4%5D%7B64%7D%20%20%3D%20%2864%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%20%3D%20%282%5E6%29%5E%7B%5Cfrac%7B1%7D%7B4%7D%20%7D%3D%202%5E%7B%5Cfrac%7B6%7D%7B4%7D%20%7D%20%3D%202%5E%7B%5Cfrac%7B3%7D%7B2%7D%20%7D%3D%28%5Csqrt%7B2%7D%20%29%5E3%20%3D%20%28%5Csqrt%7B2%7D%20%20%5Ctimes%20%5Csqrt%7B2%7D%20%20%5Ctimes%20%5Csqrt%7B2%7D%20%29%20%3D%202%5Csqrt%7B2%7D)
Thus, the equation is FALSE.
(4) ![2^8 = (\sqrt[3]{16} )^6](https://tex.z-dn.net/?f=2%5E8%20%3D%20%28%5Csqrt%5B3%5D%7B16%7D%20%29%5E6)
![2^8 = 256\\\\ (\sqrt[3]{16} )^6 = (16)^{\frac{6}{3} } = (2^4)^{\frac{6}{3} } = (2)^{\frac{24}{3} } = 2^8 = 256](https://tex.z-dn.net/?f=2%5E8%20%3D%20256%5C%5C%5C%5C%20%28%5Csqrt%5B3%5D%7B16%7D%20%29%5E6%20%3D%20%2816%29%5E%7B%5Cfrac%7B6%7D%7B3%7D%20%7D%20%3D%20%282%5E4%29%5E%7B%5Cfrac%7B6%7D%7B3%7D%20%7D%20%3D%20%282%29%5E%7B%5Cfrac%7B24%7D%7B3%7D%20%7D%20%3D%202%5E8%20%3D%20256)
Thus, the equation is TRUE.
(5) 

Thus, the equation is FALSE.