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3 years ago

Please hurry!!! If you answer first of the two I'll give you a brainliest!!!!

Mathematics

2 answers:

evablogger [386]3 years ago

6 0

9 I think I’m not to sure but yeah

NISA [10]3 years ago

6 0

(-2)^ 0 times (-3) ^-2
1/3 ^2
= 1/9

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Anyone know the answer??

Serggg [28]

Answer:

the second option

Step-by-step explanation:

in ax²+bx+c = 0:

$x = \frac{-b+-\sqrt{b^2-4ac} }{2a}$

subtract both sides by 6 to get to this form, as the right side will be left with 0

6x² + 8x - 6 = 0

here, the coefficient for x² (a) is 6, the coefficient for x (b) is 8, and the remaining number added on (c) is -6

plugging our numbers into the formula, we get

$x = \frac{-8+-\sqrt{(-8)^2-4(6)(-6)} }{2(6)}\\= \frac{-8+-\sqrt{64-(-144)} }{12} \\= \frac{-8+-\sqrt{208} }{12} \\ = \frac{-8+\sqrt{208} }{12} or \frac{-8-\sqrt{208} }{12}\\= 0.53518375848 or -1.86851709182\\= approximately -1.87, 0.54$

8 0

2 years ago

Whats 1/18 as a decimal can someone please help me

sergij07 [2.7K]

1/18 as a decimal is 0.055555555555556 because you divide one by eighteen and get that number.

Hope this helped!

6 0

3 years ago

The harbormaster wants to place buoys where the river bottom is 20 feet below the surface of the water. Complete the absolute va

Natalija [7]

Answer:

The answer is below

Step-by-step explanation:

The bottom of a river makes a V-shape that can be modeled with the absolute value function, d(h) = ⅕ ⎜h − 240⎟ − 48, where d is the depth of the river bottom (in feet) and h is the horizontal distance to the left-hand shore (in feet). A ship risks running aground if the bottom of its keel (its lowest point under the water) reaches down to the river bottom. Suppose you are the harbormaster and you want to place buoys where the river bottom is 20 feet below the surface. Complete the absolute value equation to find the horizontal distance from the left shore at which the buoys should be placed

Answer:

To solve the problem, the depth of the water would be equated to the position of the river bottom.

$d(h)=river \ bottom\\\\The \ river \ bottom=-20\ feet(below)\\\\d(h) = -20\\\\\frac{1}{5}|h-240|-48=-20\\ \\\frac{1}{5}|h-240|=-20+48\\\\\frac{1}{5}|h-240|=28\\\\|h-240|=28*5\\\\|h-240|=140\\\\h-240=140\ or\ h-240=-140\\\\h=140+240\ or\ h=-140+240\\\\h=380\ or\ h=100\\\\The\ buoys\ should\ be\ placed\ at\ 100\ feet\ and\ 380\ feet\ from\ left-hand\ shore$

4 0

4 years ago

Solve the problem.

Lorico [155]

Answer:

Step-by-step explanation:

You must use a combination:

$_nC_k=\dfrac{n!}{k!(n-k)!}$

We have <em>n = 16</em>, <em>k = 3</em>.

Substitute:

$_{16}C_3=\dfrac{16!}{3!(16-3)!}=\dfrac{13!\cdot14\cdot15\cdot16}{2\cdot3\cdot13!}\qquad\text{cancel}\ 13!\\\\=\dfrac{14\cdot15\cdot16}{2\cdot3}=\dfrac{7\cdot5\cdot16}{1}=560$

5 0

4 years ago

Which autocad command can we use to quickly calculate the area and perimeter of a closed region defined by a polyline?

polet [3.4K]

The answer is: The Area command.

The explanation is shown below:

1. The Area command is a very useful command in AutoCad, and you can use it to calculate the area and the perimeter of a closed region draw with a polyline.

2. To use this command, you only need to type AREA and press the enter button. Then, you must select the points of the closed region and press enter again. Once you do this, the software will show you the perimeter and the area.

4 0

4 years ago