Answer:
see explanation
Step-by-step explanation:
the equation of a circle in standard form is
(x - h)² + (y - k )² = r²
where (h, k ) are the coordinates of the centre and r is the radius
given
x² + y² - 8x + 8y + 23 = 0
collect the x and y terms together and subtract 23 from both sides
x² - 8x + y² + 8y = - 23
using the method of completing the square
add ( half the coefficient of the x / y terms )² to both sides
x² + 2(- 4)x + 16 + y² + 2(4)y + 16 = - 23 + 16 + 16
(x - 4)² + (y + 4)² = 9 ← in standard form
with centre = (4, - 4 ) and r =
= 3
this is shown in graph b
I m confused where is x and where is multiply sign
Answer:
6,7
Step-by-step explanation:
Answer:
maximum height of the arrow will be 408 m
Step-by-step explanation:
We have given the function of height as 
We know that first derivative of height will be velocity
So first derivative of height


We know that at maximum height velocity will be zero

t = 5 sec
Sp arrow will be at maximum height at t = 5 sec
So height at t = 5 sec will be

So maximum height of the arrow will be 408 m
12
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