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UNO [17]
3 years ago
12

Can somebody plz help answer all these questions (only if u know how to do it) lol thanks!!!

Mathematics
2 answers:
vladimir1956 [14]3 years ago
7 0

Answer:

  1. 13=6 14=5. 15=3 16=2 17=5 18= 7 19=2 20=9
allochka39001 [22]3 years ago
4 0

Answer:

13. X= 6

14. X= 5

15. X= 3

16. X= 2

17. X= 5

18. X= 7

19. X= 2

20. X= 9

Step-by-step explanation:

Divide them all. Try doing them yourself next time. I know you probably hear that a lot, but try and if you need any help don't be afraid to ask like you did. You're doing great :)

You might be interested in
A number is divisible by 2 if it can be divided by 2 without a remainder. Even numbers are divisible by 2 what is the greatest t
9966 [12]

Answer:

98

Step-by-step explanation:

I think it is 98 because it is even, and it is the second largest 2 digit number.

The largest 2 digit number, 99, isn't divisible by 2 because it is an odd number.

5 0
3 years ago
Taylor buys 6 bus tickets. He pays for the tickets with a $20 bill.
4vir4ik [10]

Answer:

20 - 6c

Step-by-step explanation:

because that shows that 6c is the cost of them and you'd take the cost of them away from how much he payed i guess

6 0
3 years ago
Read 2 more answers
Write a proportion that can be used to find the value of x. Do not solve.<br> x<br> 18<br> 32
Nuetrik [128]

Step-by-step explanation: ummnmm i think 18

6 0
2 years ago
Let f(x)=2x2−8 .
MrRa [10]
Move down c units means minus 2 from whole function

f(x) moved down 2 units means f(x)-2
so

f(x)-2=2x²-8-2
f(x)-2=2x²-10


g(x)=2x²-10
3 0
2 years ago
Read 2 more answers
Describe how both the Rational Root Theorem and Descartes’ Rules of Signs help you to find the zeros of a polynomial? Give me an
MrRa [10]

Answer:

Step-by-step explanation:

Rational Root Theorem: If the polynomial

P(x) = a n x n + a n – 1 x n – 1 + ... + a 2 x 2 + a 1 x + a 0

has any rational roots, then they must be of the form of (factors of a0/factors of an).

Example: F(x) = 4x² + 5x +2

If this polynomial has any rational roots, then they must be (factors of 2)/(factors of 4), so (±1, ±2)/(±1, ±2, ±4). So if this polynomial has any rational roots, they must be either: ±1, ±1/2, ±1/4, or ±2. Notice that this polynomial doesn't have to have any rational roots, but if it does, then the roots must fit the Rational Root Theorem.

Descartes' Rules of Signs:

a). In a polynomial, how many time the sign changes is how many positive roots the polynomial will have.

Example: 5x³ + 6x² - 2x - 1

In this expression, the sign only changed once, between 6x² and 2x, so it will only have one positive root.

Example 2: 6x³ - 4x² + x - 6

In this expression, the sign changed 3 times (remember there is a invisible "+" sign before the 6x³), so it will have 3 positive roots.

b). In a polynomial, if you plug in "-x" for all "x", then how many times the new polynomial changes sign is how many negative roots the old polynomial have.

Example: 5x³ + 6x² - 2x - 1.

If we plug in "-x" for all "x", then we get 5(-x)³ + 6(-x)² - 2(-x) -1, which simplifies to -5x³ + 6x² + 2x -1. In this new expression, the sign changed twice, so we have two negative roots for the expression. Notice how we got one positive root the first time and two negative roots the second time, and 1 + 2 = 3. The Fundamental Theorem of Algebra states that for a nth degree polynomial, it will have n complex roots. The polynomial we worked with was a 3rd degree polynomial, and we got 1 + 2 = 3 roots in the end.

4 0
3 years ago
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