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Darina [25.2K]
3 years ago
12

How do you write 3.625 as a fraction

Mathematics
2 answers:
devlian [24]3 years ago
6 0
The numbers after the decimal point are 3. That means 3 zeros as in 1000.
So now. Take away the decimal point. That will be
3625/1000
The answer is 3625/1000
But it can be divided further by 5 to be
725/200
And by 5 again to be
145/40
And again
29/8
It is 29/8 in its simplest form
Hope that helped. Have a nice day

vesna_86 [32]3 years ago
5 0
3.625 as a fraction would be 3 5/8 or 29/8.
You would get that by converting 3.625 to 3 625/1000. You do that because there is a 3 before the decimal- (that is a whole #) and three digits after the decimal (that means it goes into the thousandths place, so the denominator is 1000), Then you take the numbers after the decimal and place it over the 1000. Then you would simply the 3 625/1000 by 125. and get 3 5/8 or as a mixed # 29/8. (Multiply the 8 and 3 to get 24 and add the numerator (5) to get 29. The denominator stays the same.

Hope this helps!
Can u plz mark me as brainliest? I really need it!
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Answer:

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Step-by-step explanation:

Trey is taking out a loan for $85000. It is a 20-year loan with an APR of 5.85%.

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Answer:

The ship S is at 10.05 km to coastguard P, and 12.70 km to coastguard Q.

Step-by-step explanation:

Let the distance of the ship to coastguard P be represented by x, and its distance to coastguard Q be represented by y.

But,

<P = 048°

<Q = 360^{o} - 324^{o}

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Sum of angles in a triangle = 180^{o}

<P + <Q + <S = 180^{o}

048° + 036^{o} + <S = 180^{o}

84^{o} + <S = 180^{o}

<S  = 180^{o} -  84^{o}

    = 96^{o}

<S = 96^{o}

Applying the Sine rule,

\frac{y}{Sin P} = \frac{x}{Sin Q} = \frac{z}{Sin S}

\frac{y}{Sin P} = \frac{z}{Sin S}

\frac{y}{Sin 48^{o} } = \frac{17}{Sin 96^{o} }

\frac{y}{0.74314} = \frac{17}{0.99452}

⇒ y = \frac{12.63338}{0.99452}

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\frac{x}{Sin 36^{o} } = \frac{17}{Sin 96^{o} }

\frac{x}{0.58779} = \frac{17}{0.99452}

⇒ x = \frac{9.992430}{0.99452}

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the ship S is at a distance of 10.05 km to coastguard P, and 12.70 km to coastguard Q.

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