Answer:
C
Step-by-step explanation:
x²+2x-15 = x²-3x+5x-15 = x(x-3)+5(x-3)=(x+5)(x-3)
or delta:
∆=2²-4*1*(-15)=4+60=64
√∆=8
x1 = (-2+8)/2 = 3
x2=(-2-8)/2=-5
and 4x+20 = 4(x+5)
The same is (x+5), so it is GCF. answer C
The greatest common factor (gcf) is 6.
Answer:
do u need other coordinates?
if so B'(1,-1)
C'(1,4)
D'(5,6)
the formula is (-x,y)
hope it helps :)
Answer:
ΔABC≅ΔDEC by AAS
Step-by-step explanation:
You can use the AAS method of congruency.
Since you already have <BAC and <EDC congruent to eachother, and sides BC and EC congruent to each other, you only need that one remaining angle in between. <ACB can be proven congruent to <DCE by the Vertical Angles Theorem, and that gives you the AAS you need to prove that these two triangles are congruent
Hope this helped.
Min {sin(x) | 0 is les than or equal to x less than or greater than or equal to 2 pie = -1 at x = 3 pie over 2
