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2 years ago

Find the arc length of the partial circle.

Mathematics

1 answer:

Serga [27]2 years ago

5 0

Known :

r = 5 cm

θ = 360° - 90° = 270°

Asked :

Arc length of the partial circle = ...?

Answer :

Arc length

$= \frac{θ}{360} \times 2\pi r \\ = \frac{270}{360} \times 2 \times 3.14 \times 5 \\ = \frac{3}{4} \times 31.4 \\ = \frac{3}{4} \times \frac{314}{10} \\ = \frac{942}{40} \\ = 23.55 \: cm$

So, the arc length of the partial circle is 23,55 cm

Hope it helps and is useful :)

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barxatty [35]

Answer:

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2 years ago

A bag contains 20 slips of paper Individually numbered. If a slip of paper and a letter in the word PENNSYLVANIA is chosen at ra

Soloha48 [4]

Answer:

$P(M4\ n\ V) = 2.083\%$

Step-by-step explanation:

Given

Paper = 20 slips

Word: PENNSYLVANIA

Required

Determine P(Multiple of 4 and V)

The sample size of the 20 slips is:

$n(S) = 20$

The outcomes of multiples of 4 is:

$M4= \{4,8,12,16,20\}$

$n(M4) = 5$

So, the probability of multiples of 4 is:

$Pr(M4) = \frac{5}{20}$

$Pr(M4) = \frac{1}{4}$

The sample size of PENNSYLVANIA is:

$n(S) = 12$

The outcome of V is:

$n(V) = 1$

So, the probability of V is:

$P(V) = \frac{1}{12}$

So, the required probability is: P(Multiple of 4 and V)

$P(M4\ n\ V) = P(M4) * P(V)$

$P(M4\ n\ V) = \frac{1}{4} * \frac{1}{12}$

$P(M4\ n\ V) = \frac{1}{48}$

$P(M4\ n\ V) = 0.02083$

Express as percentage

$P(M4\ n\ V) = 0.02083 * 100\%$

$P(M4\ n\ V) = 2.083\%$

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Answer:

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1 year ago

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Answer:

wala sa choices ang sagot.

ANS: 128

EXPLANATION

a(9)=14+2(9-1)

a(9)=14+2(8)

a(9)=16(8)

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yan sagot ko po

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Answer:

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Step-by-step explanation:

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