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Nataly_w [17]
3 years ago
8

What is this!!!!!!!!!!!!

Mathematics
1 answer:
Karo-lina-s [1.5K]3 years ago
7 0

Answer:

MARK ME BRAINLIEST!! THANKS BOO!!!!!!!!!!!

Step-by-step explanation:

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Help can’t find the answer
mixer [17]

Answer:

Volume= 82.4in³

Step-by-step explanation:

Volume is the measure of the amount of space inside of a solid figure, like a cube, ball, cylinder or pyramid. It's units are always "cubic"

To find the volume of sphere, we will use the following formula of Volume:

Volume = 4/3 πr³

Put the values in the formula:

As we know that the value of π is 22/7 or 3.14

Radius = 2.7

According to the formula:

Volume = 4/3 * 3.14 *(2.7)³

Volume= 4/3* 3.14(19.683)

Volume=4/3(61.80462)

Volume=247.21848/3

Volume= 82.4in³....

3 0
3 years ago
Please help me with this question
ValentinkaMS [17]
Multiply those numbers
5 0
3 years ago
Help i dont understand this
Igoryamba
I’m not extremely good at math but I think you need to make -x-y=1 into y=mx+b form and then solve your new equation!
4 0
3 years ago
Use a proof by contradiction to show that the square root of 3 is national You may use the following fact: For any integer kirke
Ierofanga [76]

Answer:

1. Let us proof that √3 is an irrational number, using <em>reductio ad absurdum</em>. Assume that \sqrt{3}=\frac{m}{n} where  m and n are non negative integers, and the fraction \frac{m}{n} is irreducible, i.e., the numbers m and n have no common factors.

Now, squaring the equality at the beginning we get that

3=\frac{m^2}{n^2} (1)

which is equivalent to 3n^2=m^2. From this we can deduce that 3 divides the number m^2, and necessarily 3 must divide m. Thus, m=3p, where p is a non negative integer.

Substituting m=3p into (1), we get

3= \frac{9p^2}{n^2}

which is equivalent to

n^2=3p^2.

Thus, 3 divides n^2 and necessarily 3 must divide n. Hence, n=3q where q is a non negative integer.

Notice that

\frac{m}{n} = \frac{3p}{3q} = \frac{p}{q}.

The above equality means that the fraction \frac{m}{n} is reducible, what contradicts our initial assumption. So, \sqrt{3} is irrational.

2. Let us prove now that the multiplication of an integer and a rational number is a rational number. So, r\in\mathbb{Q}, which is equivalent to say that r=\frac{m}{n} where  m and n are non negative integers. Also, assume that k\in\mathbb{Z}. So, we want to prove that k\cdot r\in\mathbb{Z}. Recall that an integer k can be written as

k=\frac{k}{1}.

Then,

k\cdot r = \frac{k}{1}\frac{m}{n} = \frac{mk}{n}.

Notice that the product mk is an integer. Thus, the fraction \frac{mk}{n} is a rational number. Therefore, k\cdot r\in\mathbb{Q}.

3. Let us prove by <em>reductio ad absurdum</em> that the sum of a rational number and an irrational number is an irrational number. So, we have x is irrational and p\in\mathbb{Q}.

Write q=x+p and let us suppose that q is a rational number. So, we get that

x=q-p.

But the subtraction or addition of two rational numbers is rational too. Then, the number x must be rational too, which is a clear contradiction with our hypothesis. Therefore, x+p is irrational.

7 0
3 years ago
Definition of the math word obtuse triangel
Alexxandr [17]
An obtuse triangle is a triangle which has one obtuse angle. <span> 

Obviously, only a single angle in a </span>triangle<span> can be </span>obtuse<span> or it wouldn't be a </span>triangle.

Hope that helps you
4 0
3 years ago
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