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MakcuM [25]
3 years ago
15

A recipe called for 1/12  Cup of chopped walnuts and 3/4 cup of diced walnuts. It also called for 1/3 cup of lettuce in total

how many cups of walnuts did the recipe call for
Mathematics
1 answer:
sleet_krkn [62]3 years ago
4 0
20/20 because it’s the only right answer
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PLZ HELP! WILL GIVE BRAINLIEST!
nalin [4]

Answer:

About 2105.98

Step-by-step explanation:

31% of 3354 is 1039.74

3354-1039.74=2314.26

9% of 2314.26 is 208.2834

2314.26-2018.2834=2105.9766

4 0
3 years ago
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Line JK bisects line LM at point J. Find JM if LJ=23 centimeters
vlada-n [284]
Ling JM is also 23 centimeters because line LJ and JM are a line but broken into two segments
4 0
3 years ago
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What’s the answer to the question down below
levacccp [35]

Any linear equation can be written as

y = mx+b

where m is the slope and b is the y intercept

m = 1/2 in this case. It represents the idea that the snow fell at a rate of 1/2 inch per hour. In other words, the snow level went up 1/2 an inch each time an hour passed by.

b = 8 is the y intercept. It's the starting amount of snow. We start off with 8 inches of snow already.

The info "snow fell for 9 hours" doesn't appear to be relevant here.

3 0
3 years ago
Manny can assemble a computer by himself in 50 minutes. Lucy does the same job in 45 minutes. How long will it take to assemble
jonny [76]
Manny can assemble a computer in 50 minutes. That means, in a minute Manny does \frac{1}{50} job.

Lucy can assemble a computer in 45 minutes. That means, in a minute Lucy does \frac{1}{45} job.

If they are working together, in a minute they will do:
\dfrac{1}{50} + \dfrac{1}{45}
= \dfrac{9}{450} + \dfrac{10}{450} \text{(equalize the denominator)}
=\dfrac{19}{450}
In a minute they will do \frac{19}{450} job

To finish the job they will do it in \frac{450}{19} minutes or about 24 minutes.
5 0
3 years ago
Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and
zloy xaker [14]

Answer:

(0,0)   (4000,0) and (500,79)

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW

\frac{dW}{dt} = -0.02W + 0.00004RW

To solve this, we first equate \frac{dR}{dt} and \frac{dW}{dt} to 0.

So, we have:

0.09R(1 - 0.00025R) - 0.001RW = 0

-0.02W + 0.00004RW = 0

Factor out R in 0.09R(1 - 0.00025R) - 0.001RW = 0

R(0.09(1 - 0.00025R) - 0.001W) = 0

Split

R = 0   or 0.09(1 - 0.00025R) - 0.001W = 0

R = 0   or  0.09 - 2.25 * 10^{-5}R - 0.001W = 0

Factor out W in -0.02W + 0.00004RW = 0

W(-0.02 + 0.00004R) = 0

Split

W = 0 or -0.02 + 0.00004R = 0

Solve for R

-0.02 + 0.00004R = 0

0.00004R = 0.02

Make R the subject

R = \frac{0.02}{0.00004}

R = 500

When R = 500, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0

0.09 -0.01125 - 0.001W = 0

0.07875 - 0.001W = 0

Collect like terms

- 0.001W = -0.07875

Solve for W

W = \frac{-0.07875}{ - 0.001}

W = 78.75

W \approx 79

(R,W) \to (500,79)

When W = 0, we have:

0.09 - 2.25 * 10^{-5}R - 0.001W = 0

0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0

0.09 - 2.25 * 10^{-5}R = 0

Collect like terms

- 2.25 * 10^{-5}R = -0.09

Solve for R

R = \frac{-0.09}{- 2.25 * 10^{-5}}

R = 4000

So, we have:

(R,W) \to (4000,0)

When R =0, we have:

-0.02W + 0.00004RW = 0

-0.02W + 0.00004W*0 = 0

-0.02W + 0 = 0

-0.02W = 0

W=0

So, we have:

(R,W) \to (0,0)

Hence, the points of equilibrium are:

(0,0)   (4000,0) and (500,79)

4 0
3 years ago
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